Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (ckenn):

How do you derive the equation of a circle?

OpenStudy (michele_laino):

please you have to start from the definition of a circle: " A circle is a curve wherein the distance between each point, which belong to such circle, and another point, which is the centre of such circle, is equal to the radius of such circle"

OpenStudy (welshfella):

draw a circle on a graph with known center (not the origon) and known radius Then take any point on the graph (x,y). Use cordinate geometry and pythagoras theorem to find a relation between x and y .

OpenStudy (michele_laino):

now we can implement such definition, using the cartesian coordinates, and the euclidean distance between two points, like below: \[\Large \sqrt {{{\left( {x - {x_0}} \right)}^2} + {{\left( {y - {y_0}} \right)}^2}} = r\] |dw:1449335591460:dw|

OpenStudy (ckenn):

thank you both (: this is a great explanation

OpenStudy (michele_laino):

:)

OpenStudy (welshfella):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!