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Mathematics 10 Online
OpenStudy (iwanttogotostanford):

l

OpenStudy (iwanttogotostanford):

ANSW CHOICES ARE: 1 over the quantity x minus 3 times the quantity x plus 4 1 over the quantity x minus 3 times the quantity x plus 2 1 over the quantity x plus 4 times the quantity x minus 5 1 over the quantity x plus 2 times the quantity x minus 5

OpenStudy (iwanttogotostanford):

i think it is D but not sure

OpenStudy (mathmale):

I will convert your verbal presentation into a mathematical definition. Your use of "over" tells me that you're dealing with rational fractions. x minus 5 over x squared minus 3x minus 10 ⋅ x plus 4 over x squared plus x minus 12 Please verify whether or not the following is correct::\[\frac{ x-5 }{ x^2-3x-10 }+\frac{ 4 }{ x^2 }+x-12\]

OpenStudy (alekos):

have you attempted the question?

OpenStudy (mathmale):

It'd be well worth learning how to use Equation Editor to present expressions like this one clearly.

OpenStudy (iwanttogotostanford):

correct but the x-12 on the second part of the equation is under the 4 withx^2

OpenStudy (mathmale):

Next, look at this expression and determine how you might go about simplifying it.

OpenStudy (iwanttogotostanford):

I attempted the question and i got D

OpenStudy (alekos):

ok @mathmale, over to you

OpenStudy (iwanttogotostanford):

@alekos is it D

OpenStudy (mathmale):

\[\frac{ x-5 }{ x^2-3x-10 }+\frac{ 4 }{ x^2+x-12 }\]

OpenStudy (mathmale):

Is this correct? PLEASE: DO NOT DEAL IN ANSWERS. SHOW HOW YOU GOT YOUR RESULT. THAT'S WHAT COUNTS HERE.

OpenStudy (mathmale):

Can these two rational fractions be simplified? Combined?

OpenStudy (alekos):

mathmale will guide you

OpenStudy (iwanttogotostanford):

no it doesn't i just need the answer right now i know how to do it but i have 100 other problems to do and i just need confirmation @alekos

OpenStudy (mathmale):

I want to be helpful, but I don't deal in answers, at least not without seeing how you got your results. Could you please factor both denominators and then tell me what the LCD for the whole expression would be?

OpenStudy (iwanttogotostanford):

x-3

OpenStudy (mathmale):

I have factored the denom of the first rational function and have gotten two factors, both of which are different from yours. Try again, please. Factor x^2-3x-10.

OpenStudy (iwanttogotostanford):

im not sure

OpenStudy (mathmale):

then you're not ready to move on. That's my point. You can factor x^2-3x-10 in multiple ways: simiple factoring, completing the square, synthetic division, graphing and more. Any of these familiar to you?

OpenStudy (iwanttogotostanford):

yes synthetic division

OpenStudy (mathmale):

OK. Try using 5 as the divisor in synthetic division. Here's the setup:

OpenStudy (mathmale):

|dw:1449336095545:dw|

OpenStudy (mathmale):

Edit my drawing to display your work. If 5 is a root of the given algebraic function, then your synth. div. remainder will be zero.

OpenStudy (iwanttogotostanford):

ok

OpenStudy (iwanttogotostanford):

sorry but what are the 4 steps of synthetic division again? need a refresher

OpenStudy (mathmale):

First, where did I get the numbers I typed out in my illustration, above?

OpenStudy (iwanttogotostanford):

the 5 was the numerator of the equation and then I am not actually sure where you got the 1, 3, and 1 ! i thought we would use 1, -3, -10 or something of that sort

OpenStudy (mathmale):

Then I've made a typo. 1, -3 and -10 are correct. 5 is not the numerator; rather, 5 is a possible root, and we are using synth div to check whether it actually is a root or not.

OpenStudy (iwanttogotostanford):

oh ok

OpenStudy (mathmale):

|dw:1449336394897:dw|

OpenStudy (mathmale):

May I assume you've used the Draw utility before?

OpenStudy (iwanttogotostanford):

yes I have will do

OpenStudy (iwanttogotostanford):

|dw:1449336486924:dw|

OpenStudy (iwanttogotostanford):

then i do 5 times 1

OpenStudy (mathmale):

Yes, and put the result under the -3.

OpenStudy (mathmale):

Plese show your work in the Draw utility.

OpenStudy (iwanttogotostanford):

|dw:1449336543185:dw|

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