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Mathematics 7 Online
OpenStudy (anonymous):

Find y when x=15 if y=16 when x=30.

OpenStudy (dayakar):

question is incomplete

OpenStudy (anonymous):

Its not..Its exactly what it says...

OpenStudy (anonymous):

Its Direct Variation

OpenStudy (sasogeek):

it is complete @dayakar

OpenStudy (sasogeek):

y:15 16:30 find y?

OpenStudy (dayakar):

x ,y are in direct variation x1/y1 = x2/y2

OpenStudy (anonymous):

Ummm...I dont understand..

OpenStudy (dayakar):

15/16 = 30/y simplify it

OpenStudy (dayakar):

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OpenStudy (sasogeek):

when x=30, then y=16 if x=15, then what is the value of y that is, 30 is to 16, as 15 is to what (y)? to answer that, we do y1/x1 = y/x2 and solve for y y1=16 x1=30 x2=15 so our equation resolves to 16/30=y/15 16*15/30 = y solve for y

OpenStudy (dayakar):

in this ratio of x and y = constant

OpenStudy (dayakar):

@sasogeek my approach is also correct,i will show u

OpenStudy (sasogeek):

you approach doesn't answer the question... it is a solution, but not a solution to the problem we have here...

OpenStudy (dayakar):

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OpenStudy (sasogeek):

that makes no sense, because it's not an exponential function. it's linear. when x is 30, y is 16. how is it that when x is 15, y is 32?

OpenStudy (sasogeek):

you got it wrong from the very beginning. it's supposed to be 16:30, and not 15:16....

OpenStudy (sasogeek):

for x x1 = 30 x2 = 15 = 30/2 for y y1 = 16 y2 = 8 = 16/2 the constant is 2, and it is a multiplier.... it's a linear function

OpenStudy (dayakar):

@sasogeek plz ,can u show your work

OpenStudy (dayakar):

@sasogeek x,y are in direct variation you did it indirect variation plz check again

OpenStudy (sasogeek):

when x increases, y increases and when x decreases, y decreases 16:30 = y: 15 => 16/30 = y/15 16*15 / 30 = y 240 / 30 = y 8 = y y= 8 therefore, 16:30 = 8:15 0.53 = 0.53 (8*2) : (15*2) = 8:15

OpenStudy (dayakar):

given x=15 and y= 16 if x = 30 [increased] y=32 [increased]

OpenStudy (sasogeek):

you got it all twisted according to the question, given x=30 and y=16 then if x=15, y = what? it has to be less than 16 because x has decreased, the value of y must also decrease

OpenStudy (dayakar):

@jabez177 ,plz,do u explain whose approach is correct

OpenStudy (anonymous):

You both are confusing me....

OpenStudy (anonymous):

@mathmale Can you help please?

OpenStudy (dayakar):

@Angel360 , i am sorry, wait some time for a good explantion

OpenStudy (sasogeek):

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