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Mathematics 15 Online
OpenStudy (kittiwitti1):

http://prntscr.com/9auym5 Tried using quadratic formula and got a nonreal answer, what the heck o-0

OpenStudy (kittiwitti1):

Okay, yes; definitely a nonreal answer?! http://prntscr.com/9auzc7

jimthompson5910 (jim_thompson5910):

graph the left side as a function https://www.desmos.com/calculator then see where it crosses the x axis

jimthompson5910 (jim_thompson5910):

you can click on the roots to have the coordinates show up you'll have to zoom in to get more decimal places

OpenStudy (kittiwitti1):

http://prntscr.com/9auzw8 I think this website hates me.

jimthompson5910 (jim_thompson5910):

you have to type in `(sin(x))^2` instead of sin^2(x)

OpenStudy (kittiwitti1):

ah

OpenStudy (kittiwitti1):

http://prntscr.com/9av0c3 0-0

jimthompson5910 (jim_thompson5910):

don't enter the `=0` part just the left hand side

OpenStudy (kittiwitti1):

oh, okay

OpenStudy (kittiwitti1):

I got the equation in, what should I do now lol

OpenStudy (kittiwitti1):

I never used this site before, but it seems pretty nifty. Thanks for the reference :)

jimthompson5910 (jim_thompson5910):

click on the roots to have the coordinates show up roots = x intercepts

OpenStudy (kittiwitti1):

Okay

OpenStudy (kittiwitti1):

like this? http://prntscr.com/9av0wy

jimthompson5910 (jim_thompson5910):

wherever the graph of f(x) crosses the x axis is going to represent an approximate solution to f(x) = 0

jimthompson5910 (jim_thompson5910):

yeah but keep in mind that 0 <= x < 2pi

OpenStudy (kittiwitti1):

http://prntscr.com/9av12t

jimthompson5910 (jim_thompson5910):

still not in the right interval

OpenStudy (kittiwitti1):

eh o_o

OpenStudy (kittiwitti1):

I'm lost then xD

jimthompson5910 (jim_thompson5910):

OpenStudy (kittiwitti1):

No, I get that; but I'm not sure how to apply the limits to the graph

jimthompson5910 (jim_thompson5910):

x has to be both larger than 0 AND smaller than 2pi = 6.28 approx

OpenStudy (kittiwitti1):

ah

jimthompson5910 (jim_thompson5910):

you can click and drag to move the window of the graph

OpenStudy (kittiwitti1):

http://prntscr.com/9av1mr these?

jimthompson5910 (jim_thompson5910):

yep now just zoom in until it shows you 4 decimal places

OpenStudy (kittiwitti1):

alright!

OpenStudy (kittiwitti1):

http://prntscr.com/9av1wa Wow, this is really helpful, thanks @jim_thompson5910

jimthompson5910 (jim_thompson5910):

you nailed them both

OpenStudy (danjs):

if sin(x) = u u^2 - 3u - 3 = 0 \[u = \frac{ 3 \pm \sqrt{9-4*1*(-3)} }{ 2 }\] one works

OpenStudy (danjs):

sin(x) = u sin^(-1)(u) = x

OpenStudy (kittiwitti1):

._.;

jimthompson5910 (jim_thompson5910):

@DanJS is showing how to find the solutions without graphing

OpenStudy (kittiwitti1):

Ah. It asked for graphing though ^^;

OpenStudy (danjs):

the negative one , subtracting the root, will give you a good answer in the 0 to 2pi interval

OpenStudy (kittiwitti1):

O_O okay

OpenStudy (kittiwitti1):

Well I'd give you a medal but I already gave one to jim ;-; I'm sorry!

OpenStudy (danjs):

inverse sin of that , you get something like 0.91291 the other is a neg angle

OpenStudy (danjs):

not real

OpenStudy (danjs):

ha, thats fine,

OpenStudy (kittiwitti1):

>.<;;

OpenStudy (kittiwitti1):

But thank you for the info :D

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