Mathematics
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OpenStudy (kittiwitti1):
http://prntscr.com/9auym5
Tried using quadratic formula and got a nonreal answer, what the heck o-0
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jimthompson5910 (jim_thompson5910):
you can click on the roots to have the coordinates show up
you'll have to zoom in to get more decimal places
jimthompson5910 (jim_thompson5910):
you have to type in `(sin(x))^2` instead of sin^2(x)
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OpenStudy (kittiwitti1):
ah
jimthompson5910 (jim_thompson5910):
don't enter the `=0` part
just the left hand side
OpenStudy (kittiwitti1):
oh, okay
OpenStudy (kittiwitti1):
I got the equation in, what should I do now lol
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OpenStudy (kittiwitti1):
I never used this site before, but it seems pretty nifty. Thanks for the reference :)
jimthompson5910 (jim_thompson5910):
click on the roots to have the coordinates show up
roots = x intercepts
OpenStudy (kittiwitti1):
Okay
jimthompson5910 (jim_thompson5910):
wherever the graph of f(x) crosses the x axis is going to represent an approximate solution to f(x) = 0
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jimthompson5910 (jim_thompson5910):
yeah but keep in mind that 0 <= x < 2pi
jimthompson5910 (jim_thompson5910):
still not in the right interval
OpenStudy (kittiwitti1):
eh o_o
OpenStudy (kittiwitti1):
I'm lost then xD
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jimthompson5910 (jim_thompson5910):
OpenStudy (kittiwitti1):
No, I get that; but I'm not sure how to apply the limits to the graph
jimthompson5910 (jim_thompson5910):
x has to be both
larger than 0
AND
smaller than 2pi = 6.28 approx
OpenStudy (kittiwitti1):
ah
jimthompson5910 (jim_thompson5910):
you can click and drag to move the window of the graph
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jimthompson5910 (jim_thompson5910):
yep now just zoom in until it shows you 4 decimal places
OpenStudy (kittiwitti1):
alright!
jimthompson5910 (jim_thompson5910):
you nailed them both
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OpenStudy (danjs):
if sin(x) = u
u^2 - 3u - 3 = 0
\[u = \frac{ 3 \pm \sqrt{9-4*1*(-3)} }{ 2 }\]
one works
OpenStudy (danjs):
sin(x) = u
sin^(-1)(u) = x
OpenStudy (kittiwitti1):
._.;
jimthompson5910 (jim_thompson5910):
@DanJS is showing how to find the solutions without graphing
OpenStudy (kittiwitti1):
Ah.
It asked for graphing though ^^;
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OpenStudy (danjs):
the negative one , subtracting the root, will give you a good answer in the 0 to 2pi interval
OpenStudy (kittiwitti1):
O_O okay
OpenStudy (kittiwitti1):
Well I'd give you a medal but I already gave one to jim ;-;
I'm sorry!
OpenStudy (danjs):
inverse sin of that , you get something like 0.91291
the other is a neg angle
OpenStudy (danjs):
not real
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OpenStudy (danjs):
ha, thats fine,
OpenStudy (kittiwitti1):
>.<;;
OpenStudy (kittiwitti1):
But thank you for the info :D