What is the solution to the system of equations? https://static.k12.com/bank_packages/files/media/mathml_9126ef8d2eddfa27c0e82bd3ceed854ab4f713a1_1.gif ( , )
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pooja195 (pooja195):
Hi :)
ok so we are given 2 equations
4x+y=2 <---equation 1
x-y=3 <---equation 2
We need to isolate x in equation 2 so that we can use the substituion metho
x-y=3
Can you isolate x?
OpenStudy (anonymous):
lol could you walk me through it please
pooja195 (pooja195):
All you need to do is add y to both sides :P
pooja195 (pooja195):
What do we have once we add y to both sides?
OpenStudy (anonymous):
you have 4x+ y= 2y
x - y = 3y
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OpenStudy (anonymous):
right?
pooja195 (pooja195):
Yes but we want to isolate x so that the equation will look like x=_____
OpenStudy (anonymous):
Oh
OpenStudy (anonymous):
lol idk how to do that in this problem
pooja195 (pooja195):
to isolate x you add y to both sides
x - y = 3y
x - y +y= 3y+y
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pooja195 (pooja195):
x=4y
pooja195 (pooja195):
4x+y=2 <---equation 1
x=4y <---equation 2
now you take the value of x and plug it into equation 1
4(4y)+y=2
solve for y
OpenStudy (anonymous):
9y=2
pooja195 (pooja195):
4 x 4 =?
OpenStudy (anonymous):
8
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pooja195 (pooja195):
Multiplying...
OpenStudy (anonymous):
?
pooja195 (pooja195):
Ok let's start over
ok so we are given 2 equations
4x+y=2 <---equation 1
x-y=3 <---equation 2
To use the substitution method we need to isolate a variable look at equation 1 there is already a vairble by itself lets isolate it
all we need to do is subtract 4x from both sides now we have
y=−4x+2 <---equation 1
x−y=3 <---equation 2
Are we good so far?
OpenStudy (anonymous):
so my answer is 4,5
pooja195 (pooja195):
No. That's incorrect
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pooja195 (pooja195):
y=−4x+2 <---equation 1
x−y=3 <---equation 2
We take equation 1 and plug it into equation 2 in place of y
x-(-4x+2)-y=3
solve for x
OpenStudy (anonymous):
5x-2-y=3
OpenStudy (anonymous):
5x-y=5
pooja195 (pooja195):
There is no y my bad
5x-2=3 is correct
continue on :)
OpenStudy (anonymous):
5x=5
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OpenStudy (anonymous):
x=1
or
x=25
pooja195 (pooja195):
No we divide so x=1 is correct :)
OpenStudy (anonymous):
so my answer is one?
pooja195 (pooja195):
For x yes it is one now lets solve for y
Substitute 1 for x in y=−4x+2
y=−4x+2
y=(−4)(1)+2
OpenStudy (anonymous):
y=-2
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pooja195 (pooja195):
Well done =)
OpenStudy (anonymous):
thank you so much!
pooja195 (pooja195):
yw ^_^
OpenStudy (anonymous):
my answer is (1,-2)
pooja195 (pooja195):
Correct
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