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4 times the sum of a number and 3 is 9 less than twice the number?
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I must write this in an equation , not solving it
I'm looking at that again. I got confused...
You have 4 times the sum of a number and 3 that is written as 4(x + 3)
now the value of the above is 9 less than twice the number so 4(x + 3) = 2x - 9
Write the equation of the following statement: 4 times the sum of a number and 3 is 9 less than twice the number. This is the whole question
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you have it in my last post.
A. 4(b + 3) = 9 - 2b B. 4b + 3 = 2b - 9 C. 4(b + 3) = 2b - 9 D. 4(b - 3) = 9 - 2b it can only be one of those four
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