Write the equation of the following statement: 4 times the sum of a number and 3 is 9 less than twice the number.
A. 4(b + 3) =
9 - 2b
B. 4b + 3 =
2b - 9
C. 4(b + 3) =
2b - 9
D. 4(b - 3) =
9 - 2b
????
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OpenStudy (okdutchman7):
4(N+3) +9 = 2N
OpenStudy (okdutchman7):
Can you figure it out if I give you that?
OpenStudy (okdutchman7):
Just rearrange the equation I gave you and use b instead of n
OpenStudy (0487308):
First you have to isolate N. Do you know how to do that, or do you need me to help you with that?
OpenStudy (0487308):
Sorry, I mean N. I was looking at okdutchman7's reply XD
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OpenStudy (okdutchman7):
4(n+3) = 2n - 9
OpenStudy (mgriffin16):
its just asking me to put that sentence into a equation, i do not have to solve anything.
It will either be A,B,C, or D
OpenStudy (okdutchman7):
Change what I wrote from n to b and that is your answer
OpenStudy (okdutchman7):
I can't give you the answer directly.
OpenStudy (mgriffin16):
oh thank you
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OpenStudy (0487308):
Okay. First, you will have to subtract 9 from each side. This will give you 4(b+3) = 2b-9.