Write the equation of the following statement: 4 times the sum of a number and 3 is 9 less than twice the number. A. 4(b + 3) = 9 - 2b B. 4b + 3 = 2b - 9 C. 4(b + 3) = 2b - 9 D. 4(b - 3) = 9 - 2b ????
4(N+3) +9 = 2N
Can you figure it out if I give you that?
Just rearrange the equation I gave you and use b instead of n
First you have to isolate N. Do you know how to do that, or do you need me to help you with that?
Sorry, I mean N. I was looking at okdutchman7's reply XD
4(n+3) = 2n - 9
its just asking me to put that sentence into a equation, i do not have to solve anything. It will either be A,B,C, or D
Change what I wrote from n to b and that is your answer
I can't give you the answer directly.
oh thank you
Okay. First, you will have to subtract 9 from each side. This will give you 4(b+3) = 2b-9.
The answer is B.
Thank you very much
Okay, no problem. Do you understand now?
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