Question

Find three consecutive even integers such that three times the sum of the first and third is 24 greater than 4 times the second.

Answer 1

the first step to solving these kinds of questions is to write down some equations based on the conditions

Answer 2

lets consider the first condition: three consecutive even integers

Answer 3

ok

Answer 4

how would you represent them mathematically?

Answer 5

by variables?

Answer 6

yes

Answer 7

lets say n is an integer

Answer 8

how would you write three consecutive even integers using n?

Answer 9

n cubed?

Answer 10

you can represent even numbers as 2n+1 or 2n or 2n+2...

Answer 11

ohh ok

Answer 12

the next condition: three times the sum of the first and third is 24 greater than 4 times the second

Answer 13

so your first step would be choosing the three consecutive numbers you want to use

Answer 14

for simplicity, lets use:
1st: 2n
2nd: 2n+1
3rd: 2n+2

Answer 15

now write down the equation

Answer 16

ok

Answer 17

Now what?

Answer 18

did you write the equation?

Answer 19

yes

Answer 20

show me

Answer 21

how?

Answer 22

like this:
three times the first so, 3(2n)...continue

Answer 23

I have NO idea if I'm right but
3(2n) + (2n + 2) +24 + 4(2n+1)

Answer 24

lol im sorry i gave you the wrong lead

Answer 25

three times the sum of the first and third will be: 3(2n+2n+2)

Answer 26

oh ok

Answer 27

I'm really bad at math

Answer 28

i think it'll be easier if i give you the equation and then explain it

Answer 29

heres the equation: 3(2n+2n+2)=24+4(2n+1)

Answer 30

use this list to help you:
greater : +
is : =
times : *
sum of x and y : (x+y)

Answer 31

ok