Question

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Answer 1

You need to write a "direct proportion" formula. It will have the form y=kx, where "k" is your "constant of proportionality."

Answer 2

Would it be B? It timed.

Answer 3

"f(x) varies directly with x and f(x)=2 when x=16"

Write y=f(x)=k*x. Then substitute the knowns: Subst. 2 for f(x) and 16 for x. What is k?

I understand that you're under time pressure, but it's very important to me that you understand the principles involved.

Answer 4

f(x) = 2 = k*(16). find k, please.

Answer 5

I have no idea.

Answer 6

2=16k; find k.

Or: 16k=2; find k. Hint: divide both sides of the equation by 16.

Answer 7

\[16 k=2\]

Answer 8

1=1
so k = 1?

Answer 9

\[\frac{ 16k }{ 16 }=\frac{ 2 }{ 16 }\]

Answer 10

Please simplify this. No, k does not have the value 1. Sorry

Answer 11

1 = .0125

Answer 12

Reduce 16/16 by division. Similarly, reduce 2/16 by div.

On the left side you have the constant k.
What you want to do is to write 1k=0.0125.

Answer 13

common sense tells you that 1 does not equal 0.0125.

Answer 14

Obviously.

Answer 15

Then, either k=0.0125, or k=1/8

Answer 16

I just mean that thats what i got after.

Answer 17

*0.125

Answer 18

then your equation is y = (1/8) x.

Answer 19

Note that MysticalFlames is correct.

Answer 20

ohh okay so x would be 8?

Answer 21

Yep

Answer 22

Substitute x=4 into the equation above.

Answer 23

let x=4. If y=(1/8)x, what is y?

Answer 24

okay i have another problem,

Answer 25

Please, finish this one.

Answer 26

what is y = (1/8)*(4)?

Answer 27

32?

Answer 28

Does 4/8 = 32?

Answer 29

Reduce 4/8

Answer 30

Thus, if x=4, y=4/8 = 1/2

Answer 31

u said 1 divided by 8

Answer 32

which is 8. and 8 times 4 is 32

Answer 33

wait what nvm

Answer 34

I can give y ou only 4-5 minutes more, since I have a 5 p.m. commitment.

No... (1/8)*4 is 4/8 = 1/2. In decimal fractions, (0.125)*4 = 1/2

Answer 35

^^

Answer 36

okay thanks.

Answer 37

You're welcome.

Answer 38

There's no option for 0.5

Answer 39

Would you two please work together to find the correct answer, if 1/2 is not correct.
As explained a few minutes ago, I need to get off the 'Net.