Question

Factor the expression.

2x^2 - 6x + 4

Answer 1

Have you tried to solve that?

Answer 2

2(x^2-3x+2

Answer 3

Just confused on the 2x^2 cus I usually solve without a number in front of x.

Answer 4

You'll have to get used to that. For now, listen to @sSoyanii Factor it out of the entire expression.

Answer 5

So its 2(x-1x-2x+2)

Answer 6

How do I do the next step

Answer 7

What is that?

2x^2 - 6x + 4 = 2(x^2 - 3x + 2)

This is the Distributive Property of Multiplication over Addition.

Factor the rest: 2(x^2 - 3x + 2) = 2(x _____ _____)(x ______ _____)

Answer 8

2(x-1)(x-2)

Answer 9

How do I factor this one. 2x^2 -11x + 5

Answer 10

I think you have it.

Factor everything the same way.

Look for common factors and factor them out.

Setup what you can set up.

2x^2 - 11x + 5 = (2x ____ ____)(x ____ ____)

The two end blanks must be filled in with factors of 5. 1*5 that's it.
The two middle blanks must be the same sign, since 5 is positive.

Just keep this in mind: (ax+b)(cx+d) = acx + (ad+bc)x + bd

In your problem
1) ac = 2
2) bd = +5
3) (ad + bc) = -11

Answer 11

thank you!