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Mathematics 21 Online
OpenStudy (iwanttogotostanford):

PLZ H

OpenStudy (iwanttogotostanford):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

this is the function? \[\Large f(x) = \frac{-x^2-2x-2}{x-2}\]

OpenStudy (iwanttogotostanford):

yes! @jim_thompson5910

jimthompson5910 (jim_thompson5910):

ok so you'll type in `(-x^2-2x-2)/(x-2)` into something like https://www.desmos.com/calculator

jimthompson5910 (jim_thompson5910):

make sure you zoom out so you can see the whole graph

OpenStudy (iwanttogotostanford):

so when i type that in that is indefinitely my graph visually? @jim_thompson5910

jimthompson5910 (jim_thompson5910):

there are 2 (disconnected) branches

jimthompson5910 (jim_thompson5910):

yeah that's what the graph looks like

OpenStudy (iwanttogotostanford):

two of my answers from my choices look similar but aren't the same

OpenStudy (iwanttogotostanford):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

how are they different?

OpenStudy (iwanttogotostanford):

@jim_thompson5910 they are a tad different

jimthompson5910 (jim_thompson5910):

can you show me?

OpenStudy (iwanttogotostanford):

yea @jim_thompson5910

jimthompson5910 (jim_thompson5910):

ok post a screenshot please

OpenStudy (iwanttogotostanford):

sorry I'm getting it

jimthompson5910 (jim_thompson5910):

that's ok, take all the time you need

OpenStudy (iwanttogotostanford):

OpenStudy (iwanttogotostanford):

here is the one that i think is correct

OpenStudy (iwanttogotostanford):

would you say the same?

OpenStudy (anonymous):

When i use the equation i dont get that

OpenStudy (iwanttogotostanford):

what do u get?

OpenStudy (iwanttogotostanford):

@hippo211

OpenStudy (iwanttogotostanford):

could you draw the graph

jimthompson5910 (jim_thompson5910):

@iwanttogotostanford what does the other graph look like?

OpenStudy (iwanttogotostanford):

ok, ill give the answer choices and graphs

OpenStudy (anonymous):

ok

OpenStudy (iwanttogotostanford):

A.

OpenStudy (iwanttogotostanford):

B.

OpenStudy (iwanttogotostanford):

C.

OpenStudy (iwanttogotostanford):

D.

jimthompson5910 (jim_thompson5910):

if you plugged in x = 0, what would the value of f(0) be equal to?

OpenStudy (iwanttogotostanford):

which of the graph choices would you say it is?

jimthompson5910 (jim_thompson5910):

\[\Large f(x) = \frac{-x^2-2x-2}{x-2}\] \[\Large f(0) = \frac{-(0)^2-2(0)-2}{0-2}\] \[\Large f(0) = \underline{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }\] fill in the blank

OpenStudy (iwanttogotostanford):

i got -2/-2 but i think i did my algebra wrong

jimthompson5910 (jim_thompson5910):

-2/-2 will reduce to 1

jimthompson5910 (jim_thompson5910):

so f(0) = 1 this means that the point (0,1) is a point on the graph of f(x)

OpenStudy (iwanttogotostanford):

yes, true

jimthompson5910 (jim_thompson5910):

so use desmos to graph and use the fact that (0,1) is on the graph

OpenStudy (iwanttogotostanford):

so B would be the closest answer, correct?

jimthompson5910 (jim_thompson5910):

did you use desmos to graph?

OpenStudy (iwanttogotostanford):

yess

jimthompson5910 (jim_thompson5910):

https://www.desmos.com/calculator/l7wpprkfxw

OpenStudy (iwanttogotostanford):

now i am thinking C or D?

OpenStudy (anonymous):

thats in wrong the way you enter the info

OpenStudy (anonymous):

https://www.desmos.com/calculator/amezlkdjfr look at this

OpenStudy (iwanttogotostanford):

I'm very confused about which one it would be people

OpenStudy (iwanttogotostanford):

A, B, C or D??you both are saying different answers

jimthompson5910 (jim_thompson5910):

@hippo211 I think the first negative only applies to the x^2 (not the whole fraction)

jimthompson5910 (jim_thompson5910):

look at how I wrote out f(x) in my first post

OpenStudy (iwanttogotostanford):

@jim_thompson5910 yes, true the negative i only applied to that

OpenStudy (iwanttogotostanford):

so would it be C or D

OpenStudy (iwanttogotostanford):

really need confirmation here

jimthompson5910 (jim_thompson5910):

look at the answer choice that goes through (0,1)

OpenStudy (anonymous):

oh ok i see now yes your right

OpenStudy (iwanttogotostanford):

i honestly can't tell from the graphs @jim_thompson5910

OpenStudy (iwanttogotostanford):

0,1 i would think A @jim_thompson5910

jimthompson5910 (jim_thompson5910):

it can't be A because the lowest point on the left branch is somewhere in Q2

OpenStudy (iwanttogotostanford):

im so confused though did you look at the graphs i attached ?

jimthompson5910 (jim_thompson5910):

yes I did

jimthompson5910 (jim_thompson5910):

in choice A, the lowest point on the left upper branch is somewhere in Q1 when it should be somewhere in Q2

jimthompson5910 (jim_thompson5910):

the graph looks like this |dw:1449459906459:dw|

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