Mathematics
21 Online
OpenStudy (iwanttogotostanford):
PLZ H
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OpenStudy (iwanttogotostanford):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
this is the function?
\[\Large f(x) = \frac{-x^2-2x-2}{x-2}\]
OpenStudy (iwanttogotostanford):
yes! @jim_thompson5910
jimthompson5910 (jim_thompson5910):
make sure you zoom out so you can see the whole graph
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OpenStudy (iwanttogotostanford):
so when i type that in that is indefinitely my graph visually? @jim_thompson5910
jimthompson5910 (jim_thompson5910):
there are 2 (disconnected) branches
jimthompson5910 (jim_thompson5910):
yeah that's what the graph looks like
OpenStudy (iwanttogotostanford):
two of my answers from my choices look similar but aren't the same
OpenStudy (iwanttogotostanford):
@jim_thompson5910
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jimthompson5910 (jim_thompson5910):
how are they different?
OpenStudy (iwanttogotostanford):
@jim_thompson5910 they are a tad different
jimthompson5910 (jim_thompson5910):
can you show me?
OpenStudy (iwanttogotostanford):
yea @jim_thompson5910
jimthompson5910 (jim_thompson5910):
ok post a screenshot please
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OpenStudy (iwanttogotostanford):
sorry I'm getting it
jimthompson5910 (jim_thompson5910):
that's ok, take all the time you need
OpenStudy (iwanttogotostanford):
OpenStudy (iwanttogotostanford):
here is the one that i think is correct
OpenStudy (iwanttogotostanford):
would you say the same?
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OpenStudy (anonymous):
When i use the equation i dont get that
OpenStudy (iwanttogotostanford):
what do u get?
OpenStudy (iwanttogotostanford):
@hippo211
OpenStudy (iwanttogotostanford):
could you draw the graph
jimthompson5910 (jim_thompson5910):
@iwanttogotostanford what does the other graph look like?
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OpenStudy (iwanttogotostanford):
ok, ill give the answer choices and graphs
OpenStudy (anonymous):
ok
OpenStudy (iwanttogotostanford):
A.
OpenStudy (iwanttogotostanford):
B.
OpenStudy (iwanttogotostanford):
C.
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OpenStudy (iwanttogotostanford):
D.
jimthompson5910 (jim_thompson5910):
if you plugged in x = 0, what would the value of f(0) be equal to?
OpenStudy (iwanttogotostanford):
which of the graph choices would you say it is?
jimthompson5910 (jim_thompson5910):
\[\Large f(x) = \frac{-x^2-2x-2}{x-2}\]
\[\Large f(0) = \frac{-(0)^2-2(0)-2}{0-2}\]
\[\Large f(0) = \underline{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }\]
fill in the blank
OpenStudy (iwanttogotostanford):
i got -2/-2 but i think i did my algebra wrong
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jimthompson5910 (jim_thompson5910):
-2/-2 will reduce to 1
jimthompson5910 (jim_thompson5910):
so f(0) = 1
this means that the point (0,1) is a point on the graph of f(x)
OpenStudy (iwanttogotostanford):
yes, true
jimthompson5910 (jim_thompson5910):
so use desmos to graph
and use the fact that (0,1) is on the graph
OpenStudy (iwanttogotostanford):
so B would be the closest answer, correct?
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jimthompson5910 (jim_thompson5910):
did you use desmos to graph?
OpenStudy (iwanttogotostanford):
yess
OpenStudy (iwanttogotostanford):
now i am thinking C or D?
OpenStudy (anonymous):
thats in wrong the way you enter the info
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OpenStudy (iwanttogotostanford):
I'm very confused about which one it would be people
OpenStudy (iwanttogotostanford):
A, B, C or D??you both are saying different answers
jimthompson5910 (jim_thompson5910):
@hippo211 I think the first negative only applies to the x^2 (not the whole fraction)
jimthompson5910 (jim_thompson5910):
look at how I wrote out f(x) in my first post
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OpenStudy (iwanttogotostanford):
@jim_thompson5910 yes, true the negative i only applied to that
OpenStudy (iwanttogotostanford):
so would it be C or D
OpenStudy (iwanttogotostanford):
really need confirmation here
jimthompson5910 (jim_thompson5910):
look at the answer choice that goes through (0,1)
OpenStudy (anonymous):
oh ok i see now yes your right
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OpenStudy (iwanttogotostanford):
i honestly can't tell from the graphs @jim_thompson5910
OpenStudy (iwanttogotostanford):
0,1 i would think A @jim_thompson5910
jimthompson5910 (jim_thompson5910):
it can't be A because the lowest point on the left branch is somewhere in Q2
OpenStudy (iwanttogotostanford):
im so confused though did you look at the graphs i attached ?
jimthompson5910 (jim_thompson5910):
yes I did
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jimthompson5910 (jim_thompson5910):
in choice A, the lowest point on the left upper branch is somewhere in Q1
when it should be somewhere in Q2
jimthompson5910 (jim_thompson5910):
the graph looks like this
|dw:1449459906459:dw|