Express each number in terms of i.
1. √-32
2. 2√ -18
3. √ -1/9
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jagr2713 (jagr2713):
Hey what do you think we do first?
OpenStudy (joshoyen):
Uh, i really am not sure
jagr2713 (jagr2713):
Well "i" is another term for -1
so we have \[\sqrt{-32}\]
what do you think we do with the i?
OpenStudy (joshoyen):
Multiply it with √ -32?
jagr2713 (jagr2713):
Yes so when we do that, it become postive but first, what do we do with the 32?
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OpenStudy (joshoyen):
simplify?
jagr2713 (jagr2713):
Yes so what do we get?
OpenStudy (joshoyen):
uhm not sure how to do that, i forgot
jagr2713 (jagr2713):
Well to do that we need to find 2 numbers that multiply to get 32 BUT one of them has to be able to be sqrt.
OpenStudy (joshoyen):
8 and 4
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jagr2713 (jagr2713):
Great, can we simplify more?
jagr2713 (jagr2713):
wait no
jagr2713 (jagr2713):
we need one number of the 2 that can be sqrt
jagr2713 (jagr2713):
For example, lets say we have \[\sqrt{18}\]
6,3,9,2 go into it.
But only one of them can be sqrt which is 9
\[\sqrt{9}=3\]
so we are left with \[3\sqrt{2}\]
jagr2713 (jagr2713):
Do you get it?
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OpenStudy (joshoyen):
so it's √ 16 for 32 right?
jagr2713 (jagr2713):
COrrect and sqrt16 is?
OpenStudy (joshoyen):
4
jagr2713 (jagr2713):
so now 4 have been sqrt so we only have 2 left and that stays under the sqrt.
And we bring the "i" outside so what would i answer be?
OpenStudy (joshoyen):
Wait what do you mean we have 2 left,
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jagr2713 (jagr2713):
we had 16*2 and we only can sqrt 16 so 2 stays
jagr2713 (jagr2713):
16*2=32
OpenStudy (joshoyen):
ohh i see now
OpenStudy (joshoyen):
So it's 4√ 2
jagr2713 (jagr2713):
you forgot the i D:
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OpenStudy (joshoyen):
oh lol 4i√ 2
jagr2713 (jagr2713):
Correct :D
jagr2713 (jagr2713):
Ok #2
what would we get?
OpenStudy (joshoyen):
3i√ 2
OpenStudy (joshoyen):
Then would it be 2x3i√ 2
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jagr2713 (jagr2713):
Yes so whats 3*2 i
OpenStudy (joshoyen):
6i√ 2
jagr2713 (jagr2713):
Correct :D
#3?
OpenStudy (joshoyen):
oh uhm not sure how to do this one
jagr2713 (jagr2713):
what is 9sqrt?
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OpenStudy (joshoyen):
3
jagr2713 (jagr2713):
what is -1(-1)
OpenStudy (joshoyen):
1
jagr2713 (jagr2713):
remember -1 is "I" so its i so we have for the answer?
OpenStudy (joshoyen):
1/3i
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jagr2713 (jagr2713):
no -1(i) ?
OpenStudy (joshoyen):
oh -1(i) is -1(-1) which is 1?
jagr2713 (jagr2713):
-3(i) = 3i so -1(i) = i
OpenStudy (joshoyen):
ohh okay
jagr2713 (jagr2713):
So \[\frac{ i }{ 3 }\]
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jagr2713 (jagr2713):
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OpenStudy (joshoyen):
Thanks so much !
jagr2713 (jagr2713):
If you need more expert help, i would recommend out Qualified helpers :D For only 1.99 you can get expert help and a better understanding of the concept.
OpenStudy (joshoyen):
Oh really? Is it an only pay once thing?
OpenStudy (joshoyen):
or do i have to pay everytime
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jagr2713 (jagr2713):
Its a pay once thing, might change over time but you will receive great help and a better understanding