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Mathematics
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algebra
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start by distributing the (3/2)
(3/2)(x-4) = ?
3x/2−6
good now we have y + 6 = (3x/2) - 6 then subtract 6 from both sides
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*actually, add 6, not subtract
im having with the last number
its not 6 0r -6
oh, well, if you want to use 3 and 2 as coefficients then
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going back where we left off y + 6 = (3x/2) - 6 multiply both sides by 2 gives us: 2y + 12 = 3x - 12 then we subtract 2y to get 12 = 3x - 2y - 12 then we just add 12 to get 24 = 3x - 2y so your missing number is 24
that correct holy it was tricky
distribute the -2 first -2(x+6) = ?
still there?
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