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Find the constant necessary to make a perfect square trinomial. 2c^2+7c+__
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49/4 right
HI!!
if you want to write it as a perfect square you have to factor out the 2 first and start with \[2(x^2+\frac{7}{2}x)\]
take my medals
and then square it
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then half of \(\frac{7}{2}\)is \(\frac{7}{4}\) square that and get \[\frac{49}{16}\]
the square will be \[2(x+\frac{7}{4})^2\]
you are correct
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