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Calculus1
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How to solve y'=y+x(y')+2x I'm having trouble moving the y'. Thanks :)
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I have tried subtracting xy' but that cancels out the y'
My teacher some how got 2(dy^2/dx)=(y+2x)/2
Sorry my teacher divided by 2 on bith sides
\[y' = y + x y' + 2x\]\[y' - x y' = y + 2x\]\[y'(1-x) = y+2x\]is that what you needed?
Okay thank you i was just thinking about it wrongly. This is what I needed thank you
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