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Geometry 10 Online
OpenStudy (anonymous):

http://prntscr.com/9ckmwc

OpenStudy (anonymous):

pretty sure it is b

OpenStudy (anonymous):

any other opinions?

OpenStudy (anonymous):

I would help but i cant get the page to open

Nnesha (nnesha):

do you know how to complete the square ??

OpenStudy (anonymous):

What are the center and radius of the circle defined by the equation ? x^2=y^2-6x+10y+25=0 A. Center (3, -5); radius 3 B. Center (-3, 5); radius 3 C. Center (-3, 5); radius 9 D. Center (3, -5); radius 9

OpenStudy (anonymous):

no, pls explain

OpenStudy (anonymous):

no medal?

Nnesha (nnesha):

first move the constant term to the right side and then x's and y's terms together \[\large\rm \color{Red}{(x^2-6x)}+\color{blue}{(y^2+10y)}=-25\] i just subtracted 25 both sides

OpenStudy (anonymous):

im still not sure on the answer

Nnesha (nnesha):

now make the both parentheses trinomial by completing the square to complete the square you need to take half of x term and then square it in other words add (b/2)^2 to the opposite side

OpenStudy (anonymous):

no clue

Nnesha (nnesha):

for example for first one \[\large\rm \color{Red}{(x^2-6x)}+\color{blue}{(y^2+10y)}=-25\] (x^2-6x) where b is -6 takle half\[(x+\frac{b}{2})^2\] of b which is -3 and then take square of it 3^2= 9 now add 9 to the opposite side \[\large\rm \color{Red}{(x^2-6x+9)}+\color{blue}{(y^2+10y)}=-25\color{Red}{+9}\] and now you can factor (x^2-6x+9) or in short form when we complete the square the factor of trinomal would always be \[\rm (x+\frac{b}{2})^2 \] do the same with y's values

OpenStudy (anonymous):

im just dumb ):

Nnesha (nnesha):

you're not dumb you're not trying that's it

OpenStudy (anonymous):

lol, but thanks for helping

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