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Geometry 18 Online
OpenStudy (anonymous):

Need some help on this question.

OpenStudy (anonymous):

Hillary is using the figure shown below to prove Pythagorean Theorem using triangle similarity: In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC. *picture here* Which of these could be a step to prove that BC^2 = AB^2 + AC^2? 1. By the addition property of equality, AC^2 plus AD^2 = AB multiplied by DC plus AD^2. 2. By the addition property of equality, AC^2 plus AD^2 = BC multiplied by DC plus AD^2. 3. By the addition property of equality, AC^2 plus AB^2 = AB multiplied by DC plus AB^2. 4. By the addition property of equality, AC^2 plus AB^2 = BC multiplied by DC plus AB^2.

OpenStudy (anonymous):

OpenStudy (anonymous):

umm porbably not but calm down this stuff is old 4 me

OpenStudy (anonymous):

Nvm I got it

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