HELP! :( The 50th term of an arithmetic sequence is 86, and the common difference is 2. Find the first three terms of the sequence
\[t _{n}=a+(n-1)d,86=a+(50-1)*2,a=?\] this is first term next two terms are a+2,a+2+2
Thank you! :)
This is an arithmetic sequence involving only whole numbers...how did you get a decimal?
You might be thinking about a geometric sequence.
Think about it this way: If 86 is the 50th term, and 2 is the common difference, then what would the 49th term be?
Remember: arithmetic sequence. It only adding or subtracting to get to the next term.
it only requires*
Close! But you're just a little bit off.
Try this: \[a _{n} - n(d)\] where \[a _{n}\] is the nth term, n is the term (50), and d is the common difference.
-14!?
Correct!
Oh my god I am so sorry it is -12
I miscalculated xD
SORRY
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