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Mathematics 13 Online
OpenStudy (azionne):

3y + 5 < 10 will medal

OpenStudy (just_one_last_goodbye):

This should help you ^_^ http://i.imgur.com/UOhixD4.png

OpenStudy (xmissalycatx):

Subtract 5 from both sides which gives you 3y < 5 Then divide both sides by 3 and you'd get y < ?? (Hint: it will be a fraction)

OpenStudy (anonymous):

Here is a website to help: https://mathway.com/ P.S. Your answere is y<5/3

OpenStudy (xmissalycatx):

@lalovela Don't give direct answers..

OpenStudy (just_one_last_goodbye):

@xMissAlyCatx medal for medal? ^_^

OpenStudy (anonymous):

@xMissAlyCatx Sorry

OpenStudy (xmissalycatx):

Of course my dearest @just_one_last_goodbye <3

OpenStudy (just_one_last_goodbye):

Thank you ^_^

OpenStudy (azionne):

it has to be an equality and im new to this stuff

OpenStudy (xmissalycatx):

It is an inequality. All you need to do is subtract 5 from 3y + 5 and subtract 5 from 10 which gives you 3y < 5 and then you divide 3y and 5 by 3.. so you'd get y < __?__

OpenStudy (anonymous):

It fine! You will get the hang of it. ; )

OpenStudy (azionne):

well can someone walk me through this

OpenStudy (azionne):

im new at it

OpenStudy (anonymous):

i will

OpenStudy (azionne):

thx

OpenStudy (anonymous):

so first get y by its self

OpenStudy (azionne):

and how exactly do u do that

OpenStudy (anonymous):

3y+5 -3 -3 --- --- y 2

OpenStudy (anonymous):

2-2=0

OpenStudy (azionne):

Ugh im feeling slow today

OpenStudy (anonymous):

y=2

OpenStudy (xmissalycatx):

|dw:1449844044906:dw|

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