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Mathematics 12 Online
OpenStudy (anonymous):

Help me please!!

OpenStudy (xhawaiiangirlx):

irst factor out the 2 to get: ⟹2(x2+7xy−18y2)=2(x+By)(x−2y) Dividng both sides by 2 yields: ⟹x2+7xy−18y2=(x+By)(x−2y) Now expand the right hand side (expand the factored equation): ⟹x2+7xy−18y2=x2−2xy+Bxy−2By2 Now let's factor out the 'xy' from the second and third terms: ⟹x2+7xy−18y2=x2+(B−2)xy−2By2 Now let's compare coefficients; We know that that the right and left quadratics are both identical hence the coefficient of xy must be the same in both. This then implies: B−2=7⟹B=9 Similarly, you could also compare the coefficients of y2 in both quadratic which also yields the same answer: 2B=18⟹B=9

OpenStudy (anonymous):

b=9

OpenStudy (anonymous):

@iGreen , @Michele_Laino

OpenStudy (xhawaiiangirlx):

So ya its 9

OpenStudy (anonymous):

Thanks guys!

OpenStudy (xhawaiiangirlx):

Yw

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