Question

Check answer?

Answer 1

I think it's 0 but I feel like I'm wrong

Answer 2

@jim_thompson5910

Answer 3

Did we draw right triangles?

Answer 4

Yes, and tried graphing

Answer 5

using a calculator, what is the value of

\[\Large \tan^{-1}\left(\frac{\sqrt{3}}{3}\right)\]

Answer 6

26.1?

Answer 7

make sure your calculator is in degree mode

Answer 8

btw you can type `arctan(sqrt(3)/3) in degrees` into google and google acts like a calculator. Tell me what result google says

Answer 9

that is if you aren't sure how to change from radians to degrees on your original calculator

Answer 10

30 degrees it says

Answer 11

yep, now compute the arcsine of 1/2

Answer 12

0.78 radians

Answer 13

remember: you need to be in degree mode

Answer 14

if you are using google, type in `arcsin(1/2) in degrees`. You have to put "in degrees" at the end to tell google to report the result in degree mode

Answer 15

still coming up 30 degrees

Answer 16

yes, so

\[\Large {\color{blue}{\tan^{-1}\left(\frac{\sqrt{3}}{3}\right)}} = {\color{blue}{30^{\circ}}}\]

\[\Large {\color{green}{\sin^{-1}\left(\frac{1}{2}\right)}} = {\color{green}{30^{\circ}}}\]


which means


\[\Large \cos\left({\color{blue}{\tan^{-1}\left(\frac{\sqrt{3}}{3}\right)}} + {\color{green}{\sin^{-1}\left(\frac{1}{2}\right)}}\right)\]


\[\Large =\cos\left({\color{blue}{30^{\circ}}} + {\color{green}{30^{\circ}}}\right)\]


\[\Large =\cos\left(60^{\circ}\right) = ???\]

Answer 17

1/2

Answer 18

correct

Answer 19

that's your final answer

Answer 20

Omg thank you. I don't even know how I got what I got