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Biology 16 Online
OpenStudy (anonymous):

punnett squares help?

OpenStudy (dangerousjesse):

What is it that you don't understand?

OpenStudy (anonymous):

OpenStudy (dangerousjesse):

Each square is 25%. The parents are both heterozygous, which means they carry, but don't show, recessive traits. How many of their children are heterozygous as well?

OpenStudy (dangerousjesse):

Oops, scratch that. They're asking about phenotypes. How many homozygous dominant and heterozygous offspring are there?

OpenStudy (anonymous):

I am bad at punnett squares... and learning them

OpenStudy (dangerousjesse):

That's fine!

OpenStudy (dangerousjesse):

I love explaining them. The dominant trait is the big R, while the recessive trait is the little r. Whenever you have a heterozygous parent, you have a big R and a little r, Rr.

OpenStudy (anonymous):

so then wouldnt the answer be 50%?

OpenStudy (dangerousjesse):

A heterozygous parent will carry the recessive trait and show the dominant trait, since big R almost always beats little r.

OpenStudy (dangerousjesse):

No, you're looking at the genotype. They're asking about the phenotype, how the offspring will look.

OpenStudy (dangerousjesse):

Let's say the big R is a red flower and the little r is a white flower. We won't go into incomplete dominance, since that's probably later in the unit. When the parent is RR, they are red; when a parent is Rr, they are red; and when a parent is rr, they are white.

OpenStudy (dangerousjesse):

Both parents are Rr, so their offspring include one RR, two Rr, and one rr. Based on what I just told you, how many of those offspring will be red?

OpenStudy (anonymous):

3?

OpenStudy (dangerousjesse):

Yep, and what percent is 3/4?

OpenStudy (anonymous):

so then 75%?

OpenStudy (dangerousjesse):

Yep :)

OpenStudy (anonymous):

Thank you so much. Could you help me some more?

OpenStudy (dangerousjesse):

Sure, I love genetics.

OpenStudy (anonymous):

OpenStudy (anonymous):

would this be 25%?

OpenStudy (dangerousjesse):

Yep :) Nice job

OpenStudy (anonymous):

OpenStudy (dangerousjesse):

Do you know how to set up a Punnet square?

OpenStudy (anonymous):

kind of

OpenStudy (dangerousjesse):

|dw:1450205701395:dw|

OpenStudy (dangerousjesse):

|dw:1450205825264:dw|

OpenStudy (dangerousjesse):

You'll combine the two traits linked together in each box, like so:|dw:1450205980428:dw|

OpenStudy (dangerousjesse):

I'm sorry if the drawing is confusing, I can't use differently colored pens ;-;

OpenStudy (dangerousjesse):

But you can see from it that there is one PP, two Pp, and one pp.

OpenStudy (anonymous):

so im guessing the answer is D?

OpenStudy (dangerousjesse):

Yep, can you see why?

OpenStudy (dangerousjesse):

Okay. When you're writing a Punnet square, you put one one the parent's genotypes (Rr in this case) on top, and the other parent's genotype (also Rr) on the left side.

OpenStudy (dangerousjesse):

When you're going through each of the squares to write the offspring's genotype, you'll see whether there's a recessive or dominant trait above, then you'll look to see whether there's a dominant or recessive trait to the left.

OpenStudy (dangerousjesse):

You completely ignore the other offspring's squares, only looking at the parents' genotypes. If you see one dominant trait (big R) above and one recessive trait (little r) to the left, you'll write Rr in that square. If you see the little r above and the big R to the left, you'll write the same thing.

OpenStudy (anonymous):

Oh okay I get it I think lol

OpenStudy (dangerousjesse):

Awesome :) Let me know if you have any more trouble

OpenStudy (anonymous):

I have 2 more questions I think on the same subject I need help with. I have them answered I just don't know if they are correct or not

OpenStudy (dangerousjesse):

Cool, shoot 'em.

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

^ that one I think is B

OpenStudy (dangerousjesse):

You got that one right with A, the Law of Dominance is Mendel's third law, and it basically says that any genotype that isn't homozygous recessive (tt) will show the dominant trait.

OpenStudy (anonymous):

okay

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