Question

Given

Answer 1

@Cardinal_Carlo

Answer 2

The axis of symmetry is always the vertex of a quadratic, and the vertex is where the slope of the quadratic equals zero (m = 0). So let's find the m-value (slope) of each function:
\[f(x) = x ^{2} + 6x − 1\]
\[m = 2\left( x + 3 \right)\]
\[x = -3 ~~~when ~~m = 0\]

now for g(x):
\[g(x) =~ –x ^{2} + 2\]
\[m = -2x\]
\[x = 0 ~~~when ~~m = 0\]

now for h(x):
\[h(x) = 2x ^{2} − 4x + 3\]
\[m = 4\left( x - 1 \right)\]
\[x = 1 ~~~when ~~m = 0\]
So from least to greatest based on their axis of symmetry, the order goes as follows:
\[f(x), ~g(x), ~h(x)\]