Question

quadratic equation with roots -1+4i and -1-4i?

Answer 1

(-1+4i)(-1-4i)

Answer 2

Can you help me with three more??

Answer 3

I'll fan and medal!

Answer 4

find the zeroes of the equation
-3x^4+27x^2+1200=0

Answer 5

On the first one i meant:

(x-(-1+4i))(x-(-1-4i))
=(x+1-4i)(x+1+4i)

because if like a is a root then, x-a is a factor

Answer 6

-3(x^4-9x^2-400)=0
-3((x^2)^2-9x^2-400)=0
-3(x^2-9/2)^2 - (9/2)^2-400=0
-3(x^2-9/2)^2 - (1681/4)=0
-3(x^2-9/2)^2- (41/2)^2=0
-3(x^2+16)(x^2-25)=0

x=5, x=-5 and x=4i, x=-4i

Answer 7

I used complete square method, to solve it