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Mathematics 6 Online
OpenStudy (thehollywoodstud):

need help will Fan and Medal

OpenStudy (littleheron):

What is your question?

OpenStudy (thehollywoodstud):

OpenStudy (littleheron):

4 is prove

OpenStudy (thehollywoodstud):

can you help me @GabeBae

OpenStudy (xapproachesinfinity):

4 is ASA

OpenStudy (xapproachesinfinity):

first we were given angle congruency and a side

OpenStudy (thehollywoodstud):

and 5 is cpctc

OpenStudy (xapproachesinfinity):

then 3 they proved another angle congruency so in 4 we have angle side angle gives two congruent triangles

OpenStudy (thehollywoodstud):

and can u also help me with this one too?

OpenStudy (xapproachesinfinity):

well for 5 you have congruent triangle therefore all respective sides are congruent

OpenStudy (thehollywoodstud):

so am i right then ?

OpenStudy (xapproachesinfinity):

what is cpctc?

OpenStudy (xapproachesinfinity):

sorry not familiar with this abreviation

OpenStudy (thehollywoodstud):

Corresponding parts of congruent triangles are congruent

OpenStudy (thehollywoodstud):

does that help?

OpenStudy (xapproachesinfinity):

yes good same as i said

OpenStudy (xapproachesinfinity):

thanks :)

OpenStudy (thehollywoodstud):

ok so how about this one ?

OpenStudy (xapproachesinfinity):

okay for the next one 2 we know that all right angles are congruent 90 degrees

OpenStudy (xapproachesinfinity):

3 is given

OpenStudy (thehollywoodstud):

ok so is that what i put ?

OpenStudy (xapproachesinfinity):

yea

OpenStudy (xapproachesinfinity):

4 DSH congruent to DST

OpenStudy (xapproachesinfinity):

angles of course

OpenStudy (thehollywoodstud):

ok so 5 is ?

OpenStudy (xapproachesinfinity):

5 is SAS

OpenStudy (thehollywoodstud):

ok yeah that makes sense...

OpenStudy (xapproachesinfinity):

no sorry AAS

OpenStudy (thehollywoodstud):

so i have two more i need help with

OpenStudy (xapproachesinfinity):

ok

OpenStudy (thehollywoodstud):

here is the first one

OpenStudy (xapproachesinfinity):

Do you agree that we have isos triangle

OpenStudy (thehollywoodstud):

yes

OpenStudy (thehollywoodstud):

,not all of the sums of the angles are equal

OpenStudy (xapproachesinfinity):

good! do you agree that angles at the base are congruent

OpenStudy (thehollywoodstud):

yes

OpenStudy (xapproachesinfinity):

then do you see that x+x+38=180

OpenStudy (thehollywoodstud):

yes

OpenStudy (xapproachesinfinity):

so 2x=180-38

OpenStudy (xapproachesinfinity):

x=?

OpenStudy (thehollywoodstud):

71?

OpenStudy (xapproachesinfinity):

correct

OpenStudy (thehollywoodstud):

so is that my answer?

OpenStudy (xapproachesinfinity):

yes for sure! we started with recognizing two identical sides that told us we have isos triangle then we employed the fact that isos triangles have two congruent angles at the base then we used the fact of angles of a triangle 180 then it is reasonable what our solution is x=71

OpenStudy (thehollywoodstud):

so last one ?

OpenStudy (thehollywoodstud):

i know we have right angles

OpenStudy (xapproachesinfinity):

yes there are! but i'm going to not look at as right triangles (drawing can deceive us ) first let's look at the big triangle

OpenStudy (thehollywoodstud):

ok

OpenStudy (xapproachesinfinity):

we are given an isos triangle again

OpenStudy (thehollywoodstud):

ok

OpenStudy (xapproachesinfinity):

sorry website crash we are also given angle C=47 so B=47 then 47+47+2y=180

OpenStudy (xapproachesinfinity):

y=43

OpenStudy (xapproachesinfinity):

now focus on x x+43+47=180

OpenStudy (xapproachesinfinity):

im looking at triangle ABD

OpenStudy (xapproachesinfinity):

so it is x=90 as we thought

OpenStudy (thehollywoodstud):

ok

OpenStudy (xapproachesinfinity):

you can go with the fact angle bisector in isos triangle is perpendicular to the base

OpenStudy (xapproachesinfinity):

if you one a different method

OpenStudy (thehollywoodstud):

ok

OpenStudy (xapproachesinfinity):

so x=90 then look for y

OpenStudy (xapproachesinfinity):

read about angle bisector

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