help!!!! Solve the following system of equations using substitution x+y=5 and x+y=-3
I am the worst at this kind of thing.
I will fan and medal
ill help
thanks Prettygirl and Coolrabbit
okay the frist one x+y=5 frist step one add y to both sides x+y+−y=5+−y x=−y+5 last =y+5
ok
1. Solve one of the equations for either "x =" or "y =". 2. Replace the "y" value in the first equation by what "y" now equals. Grab the "y" value and plug it into the other equation. 3. Solve this new equation for "x". 4. Place this new "x" value into either of the original equations in order to solve for "y". Pick the easier one to work with! 5. substitute the x and y values into both original equations. If these answers are correct, both equations will be true.
x+y=-3 frist Add -y to both sides.x+y+−y=−3+−y x=−y−3 last x=-y-3
the choices are (2,3) (3,2) infinitely many No solution
is that what u mean by solving both are u want me to solv at the same time
i am not sure that is the question on my homework
oh
the question i posted is the one on my homework
so what do you think it is?
i think u post solv e at the same time
it frist x+y=5for x: x+y+−y=5+−y(Add -y to both sides) x=−y+5 then Substitute−y+5forxinx+y=−3: x+y=−3 −y+5+y=−3 5=−3(Simplify both sides of the equation) 5+−5=−3+−5(Add -5 to both sides) 0=−8 and ur final answer is 0=-8
that the answer if u put both togeether thats it
is the answer on your homework
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