Evaluate the expression, using the given value of the variable. 2 – 8x + 3x when x = 5 A. –53 B. –23 C. –15 D.57
substitute x for its value
the value for x is 5
right so replace x with 5
i did
show me what did yo uget after replacing x with 5
2 - 8x + 3x x = 5 2 - 8(5) + 3(5) = 2 - 40 + 15 = - 40 + 17 = - 23. (Correct answer B.)
i did two thing's i did 2 – 85 + 35=-48 and i did 2 – 8.5 + 3.5=4
did u look at wht i posted @cmtboy2
ya
it's 8x `8 times x` so you should multiply the 8 with x value put the parentheses
therefore the answer is B.
no
no wht
not you @dakid88
so when you replace x for 5 that's how you should write 2-8(5)+3(5) and remember the PEMDAS rule
oh
oh that i diden't do
Evaluate the expression, using the given value of the variable. z ÷ 4 – 8z + 2(z – 5) when z = 12 A. –79 B. –74 C. –34 D. 107
same here right
z ÷ 4 – 8z + 2(z – 5) (12)÷4-8(12) +2((12) -5) =-74
stop giving out answer plz
nope im helping him at the same times
let him/her learn its not ur knowledge test
there is no learning process when u provide the answer as well
im a boy thank you
lol
like i said im helping him at the same time @Nnesha thank u
don't you see cmtBOY2
there is a difference between helping and enabling
leace me alone were most focus on helping @cmtboy2
a girl can use boy word for username
ok but im a boy
how do you do this
At least try it @cmtboy2, it's the same thing as before. Substitute your variable for your value then simplify.
hey nnesha not cool dude if the guy is a guy cool if ntot cool just live with it kay:)
did you understand first question ? if you did then you shouldn't ask that question PEMDAS thats what ur teacher wants u to learn
idc if its guy or girl doesn't matter there is a reason i said /him/her its not important to know the gender
@broski532, you literally added nothing to this discussion. If you're not going to help with the question, don't bother answering.
be nice @tom982
You're joking, right? @Nnesha was doing a great job helping and @broski532 comes in making an issue out of nothing. We're here to help you guys understand maths, not cause unnecessary drama or just post answers.
am i adding (4)-2 to 12/(4)
nice \[\frac{ 12-4 }{ 12 \div 4 }\]
so i figer them out frist then i add them
2+3
what do you mean *figure them* PEMDAS P) parentheses first E)exponent 3rd MD ) multiply or divide 4th) add or subtract start with the first step is there any parentheses ? no move to the 2nd step is there any exponent ? if no then 3rd step is divide or multiply
nvm there is typo
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha nice \[\frac{ 12-4 }{ 12 \div 4 }\] \(\color{blue}{\text{End of Quote}}\) i meant \[\frac{ -4-2}{ 12 \div- 4 }\] k value is negative
-4-2=6
12/-4=-3
so now we add (-3) to 6
when the sign are the same of both numbers you should just simply add them together and then keep the same sign
-4-2= ?
-6
correct \[\frac{ \color{Red}{-4-2 }}{\color{blue}{ 12 \div -4 }}=\frac{\color{reD}{ -6 }}{ \color{blue}{-3} }\] now just simplify that
now add -6 to -3
it's not -6 `+`(-3) fraction = division
soo divide -3 to -6 right
\[\rm \frac{ \top op }{bottom }\] top part divided by the bottom -3/-6 isn't the same as -6/-3
ok thank
z ÷ 4 – 8z + 2(z – 5) when z = 12 Answer is not -74
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