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Calculus1
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Integrate 4/x^3 dx
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\[\int\limits_{?}^{?}\frac{ 4}{ x^3 }\]
this is indifinite integral so limit is not given solution is x^(n+1)/ (n+1)
\[\int\limits_{}^{}4(x)^{-3}=4\int\limits_{}^{}(x)^{-3}=(x)^{-2}/-2\]
Close. You forgot the 4 in the final answer. So I think it should be \[-2x ^{-2} +C\] I don't recall if the C is relevant or not for this question.
oh your'e right, i missed the 4 and the constant( if the integral was indefinite).
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