Question

Please help me

Simplify square root 24 minus 3 times the square root of 45 plus 2 times the square root of 20.

Answer 1

https://gyazo.com/0337b4f702f3e8ad722458f8e4f85956 equation

Answer 2

choices https://gyazo.com/2a4bc47d0c0d6ba17ba947765c6668b4

Answer 3

hint:
we have to rewrite the expression, using similar radicals

Answer 4

we can write this:
\[\Large \begin{gathered}
\sqrt {24} = \sqrt {6 \cdot {2^2}} = 2\sqrt 6 \hfill \\
\sqrt {45} = \sqrt {{3^2} \cdot 5} = 3\sqrt 5 \hfill \\
\sqrt {20} = \sqrt {{2^2} \cdot 5} = 2\sqrt 5 \hfill \\
\end{gathered} \]

Answer 5

So would it be c?

Answer 6

no, I'm sorry
Please, if I substitute, the above simplification, into your expression, I can write:
\[\huge \begin{gathered}
\sqrt {24} - 3\sqrt {45} + 2\sqrt {20} = \hfill \\
\hfill \\
= 2\sqrt 6 - 3\left( {3\sqrt 5 } \right) + 2\left( {2\sqrt 5 } \right) = ...? \hfill \\
\end{gathered} \]

Answer 7

hmm.. this is hard for me sorry. I see B

Answer 8

that's right!

Answer 9

oh awesome, thank you for helping me out!

Answer 10

:)