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Variations Just to double check my answer
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Given s varies directly w^n and s=6 when w=1. Find the value of n when s=150 and w=5.
\[s = kw^n\]Now sub \(s = 6, w =1\).\[6 = k\cdot 1^n = k\]\[\Rightarrow k = 6\]\[150 = 6\times 5^n\]\[n = \cdots\]
\[n=2\]
Good.
Thank you @ParthKohli :)
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i learn a faster way from u :) before that,i use elimination method to solve the answer Thnx @ParthKohli
Oh, I don't know what that is! But it's nice to hear you took something!
Thnx ^_^
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