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Let θ be an angle in quadrant III such that =sinθ−14. Find the exact values of secθ and tanθ.
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\(\large\rm \theta=\sin\theta-14\) Did you make a typo somewhere?
i think you must have..
sin θ = - 1/4
@welshfella
ah thats more like it
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|dw:1450620268336:dw|
sorry gtg right now
Okay I got -4/-3.87 and -1/3.87
Okay I got -4/-3.87 and -1/3.87
sec = 4/-3.87 tan = -1/3.87
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@zepdrix
the sec is correct the adjacent side = -3.87 so sec = -4/3.87
but the tangent is positive because you are dividing 2 negative numbers
tan = 1/3.87
|dw:1450621005049:dw|
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