Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (freemap):

Help

OpenStudy (freemap):

OpenStudy (freemap):

@Michele_Laino

OpenStudy (freemap):

50-20 right because I'm guessing that 50 is pod a and 20 is pod b. 50-20=30 for part(a)

OpenStudy (michele_laino):

first question from table I see population of Pod B= 20 whereas population of Pod A is greater than 50 and less than 100, we have to use a proportion

OpenStudy (freemap):

ok, 50/100 wait like 0/50 and 100/0

OpenStudy (michele_laino):

for example, using a ruler you have to measure both distances \(b\) and \(d\), then you have to apply this proportion: \(100:d=x:b\) and solve for \(x\)

OpenStudy (michele_laino):

OpenStudy (freemap):

d is 8,100 and b is 0,80

OpenStudy (michele_laino):

is it \(d=8.1\;cm\)?

OpenStudy (michele_laino):

please write both distances with the corresponding unit of measure

OpenStudy (freemap):

b=2

OpenStudy (koikkara):

@freemap wait, wait, hi... nice to meet you, btw, how you got 0/50 ?

OpenStudy (freemap):

well i thought that pod a for month 0 was 50

OpenStudy (michele_laino):

we have \(b=2\;cm\), and \(d=...?\)

OpenStudy (freemap):

8

OpenStudy (michele_laino):

it is impossible, from your drawing I think that \(d=2.5\) cm

OpenStudy (freemap):

how?

OpenStudy (michele_laino):

please I consider the proportion, namely I don't think that \[\frac{d}{b} = \frac{8}{2} = 4\]

OpenStudy (michele_laino):

I'm referring to this drawing:

OpenStudy (freemap):

thats how I got be equal 2 because off 100/80. D is 8, 100 . Okay but you says d is 2.25 ok

OpenStudy (michele_laino):

ok! So we have: \[x = \frac{{200}}{{2.25}} = ...?\]

OpenStudy (freemap):

88.88 remainder

OpenStudy (michele_laino):

ok! so we can write that population of Pod A is \(90\), I have rounded such value

OpenStudy (freemap):

ok

OpenStudy (michele_laino):

at the end of fourth month, what is the population of Pod B?

OpenStudy (freemap):

469

OpenStudy (michele_laino):

sorry, I think that, in order to answer to the third question, better is we make the graph of population of Pod B over the graph of population of Pod A

OpenStudy (freemap):

I thought we were still of part a

OpenStudy (michele_laino):

yes! of course we have to compute the subsequent difference: \(90-20=...?\)

OpenStudy (freemap):

70

OpenStudy (michele_laino):

that's right!

OpenStudy (michele_laino):

now, please I make the graph of population B, over the graph of population A, so, wait plaese

OpenStudy (freemap):

ok

OpenStudy (michele_laino):

here is it my graph:

OpenStudy (michele_laino):

so, we can say that at the end of the third month, the population of Pod B is greater than population of Pod A

OpenStudy (freemap):

ok, I see I looked at your graph

OpenStudy (michele_laino):

now, we have to answer to part B

OpenStudy (michele_laino):

do you know how is defined the growth rate?

OpenStudy (freemap):

(b) Find and compare the growth rates of each pod. Show your work. Do we just subtract the points from pod a and b?

OpenStudy (michele_laino):

no, we have to apply this definition: \[\huge r = \frac{{{V_{final}} - {V_{initial}}}}{{{V_{initial}}}} \times 100\] both of growth rates have to be evaluated inside the same time interval, which is \(9\) months

OpenStudy (michele_laino):

for example the growth rate for Pod B is: \[\huge r = \frac{{24145 - 20}}{{20}} \times 100 = ...?\]

OpenStudy (freemap):

r=119.75*100=11975

OpenStudy (michele_laino):

I got \(r=120,625\;\%\)

OpenStudy (michele_laino):

am I right?

OpenStudy (freemap):

yes

OpenStudy (freemap):

I have to restart my computer, somethings going on. It should take about 7 min. Please stay

OpenStudy (michele_laino):

now, using a ruler, please measure this distance, directly on your graph:

OpenStudy (michele_laino):

namely, the length of the orange bar

OpenStudy (freemap):

I'm back It didn't take that long, hopefully everythings fine now

OpenStudy (michele_laino):

no problem :) did you get such distance?

OpenStudy (freemap):

it looks like 9,620

OpenStudy (michele_laino):

is it \(9.62\) cm?

OpenStudy (freemap):

yes

OpenStudy (michele_laino):

I think it is a too little value, nevertheless,from the graph, we see that the population at the end of the ninth month, is about 625, so the corresponding growth rate, is: \[\huge {r_A} = \frac{{625 - 90}}{{90}} \times 100 = ...?\]

OpenStudy (freemap):

594.44 remainder

OpenStudy (michele_laino):

ok! It is \(594.44\;\%\) whereas the growth rate of Pod B, is: \[{r_B} = \frac{{24145 - 20}}{{20}} \times 100 = 120,625\% \] now, is the growth rata A less or greater than the growth rate B?

OpenStudy (freemap):

greater a doesnt have a decimal but a comma meaning thousands

OpenStudy (michele_laino):

that's right! \(r_B>r_A\)

OpenStudy (freemap):

Thank you

OpenStudy (michele_laino):

:)

OpenStudy (freemap):

part C would be 4 right

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!