Help
@Michele_Laino
50-20 right because I'm guessing that 50 is pod a and 20 is pod b. 50-20=30 for part(a)
first question from table I see population of Pod B= 20 whereas population of Pod A is greater than 50 and less than 100, we have to use a proportion
ok, 50/100 wait like 0/50 and 100/0
for example, using a ruler you have to measure both distances \(b\) and \(d\), then you have to apply this proportion: \(100:d=x:b\) and solve for \(x\)
d is 8,100 and b is 0,80
is it \(d=8.1\;cm\)?
please write both distances with the corresponding unit of measure
b=2
@freemap wait, wait, hi... nice to meet you, btw, how you got 0/50 ?
well i thought that pod a for month 0 was 50
we have \(b=2\;cm\), and \(d=...?\)
8
it is impossible, from your drawing I think that \(d=2.5\) cm
how?
please I consider the proportion, namely I don't think that \[\frac{d}{b} = \frac{8}{2} = 4\]
I'm referring to this drawing:
thats how I got be equal 2 because off 100/80. D is 8, 100 . Okay but you says d is 2.25 ok
ok! So we have: \[x = \frac{{200}}{{2.25}} = ...?\]
88.88 remainder
ok! so we can write that population of Pod A is \(90\), I have rounded such value
ok
at the end of fourth month, what is the population of Pod B?
469
sorry, I think that, in order to answer to the third question, better is we make the graph of population of Pod B over the graph of population of Pod A
I thought we were still of part a
yes! of course we have to compute the subsequent difference: \(90-20=...?\)
70
that's right!
now, please I make the graph of population B, over the graph of population A, so, wait plaese
ok
here is it my graph:
so, we can say that at the end of the third month, the population of Pod B is greater than population of Pod A
ok, I see I looked at your graph
now, we have to answer to part B
do you know how is defined the growth rate?
(b) Find and compare the growth rates of each pod. Show your work. Do we just subtract the points from pod a and b?
no, we have to apply this definition: \[\huge r = \frac{{{V_{final}} - {V_{initial}}}}{{{V_{initial}}}} \times 100\] both of growth rates have to be evaluated inside the same time interval, which is \(9\) months
for example the growth rate for Pod B is: \[\huge r = \frac{{24145 - 20}}{{20}} \times 100 = ...?\]
r=119.75*100=11975
I got \(r=120,625\;\%\)
am I right?
yes
I have to restart my computer, somethings going on. It should take about 7 min. Please stay
now, using a ruler, please measure this distance, directly on your graph:
namely, the length of the orange bar
I'm back It didn't take that long, hopefully everythings fine now
no problem :) did you get such distance?
it looks like 9,620
is it \(9.62\) cm?
yes
I think it is a too little value, nevertheless,from the graph, we see that the population at the end of the ninth month, is about 625, so the corresponding growth rate, is: \[\huge {r_A} = \frac{{625 - 90}}{{90}} \times 100 = ...?\]
594.44 remainder
ok! It is \(594.44\;\%\) whereas the growth rate of Pod B, is: \[{r_B} = \frac{{24145 - 20}}{{20}} \times 100 = 120,625\% \] now, is the growth rata A less or greater than the growth rate B?
greater a doesnt have a decimal but a comma meaning thousands
that's right! \(r_B>r_A\)
Thank you
:)
part C would be 4 right
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