Question

A system of equations is shown below:

2x = −y + 6
−4x + 3y = 8

What is the solution to this system of equations?
(−1, −4)
(1, 4)
(4, 1)
(−4, −1)

Answer 1

2x = −y + 6 <---equation 1
−4x + 3y = 8 <---equation 2
Since @loverlarap mentioned substitution we'll use it :)
Start by isolating a vairble like this:
Solve 2x=−y for y:
2x+y=−y+6+y(Add y to both sides)
2x+y=6
2x+y+−2x=6+−2x(Add -2x to both sides)
y=−2x+6
Now you have one new equation +the old one

y=-2x+6 <---equation 1
−4x + 3y = 8 <----equation 2
Take the y equals part and plug it into equation 2
as we are substituting
-4x+3(-2x+6)=8
solve for x

Answer 2

Try substituting your answers in to the equations and see if it is equal.

Answer 3

sorry for the late reply @pooja195 @Lovelarap -4x+3(-2x+6)=8 ..... x = 1

Answer 4

yes,continue.

Answer 5

what was the other equation? i got a little confused with all the words lol

Answer 6

substitute x=1 in to one of the equations and you should get y.