How to find y intercept, symmetry point, and axis of symmetry
here is an example \[y=x ^{2}-2x-3\]
V(1,-4)
Are you asking how to find the y-intercept in this problem or just any problem in general?
How can I find y-int, sym point, and axis of sym.?
well pretty much both lol
The y-int is (0-3) but, why is x 0?
(0,-3)*
Is x=0 because it's only on the y axis?
in other words, when it comes to finding the y-intercept, x is always 0?
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@DF001 Have you ever seen a graph that shows the y-intercept? Have you heard of y = mx + b?
yes but i never really knew what an y-intercept is
The y-intercept is when the line crosses into the y-axis
For example:
I notice how many questions involving this topic, x value is always 0 for y-intercept
do you notice the y-intercept? (Where the line goes into the y-axis)
oh so I was correct. x is always 0 an y-int
yes i see, y-int is the point that intersect the line
I am not sure what you mean, however, the y-intercept can be any number of the graph...as well as 0. For example: y =2x + 0, can be seen as y =2x.
I hope you understand.
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