No one is in Physics, so I am posting this here, can anyone help?
Compare the equation for a line through the origin, y = mx, to the equation Fc= mv^2/r, and explain what the slope of the graph of Fc vs. v2 represents. Remember that the m in the equation for a line represents the slope, and the m in the centripetal force equation represents the mass of the stopper.

I don't understand what they are asking

Question

No one is in Physics, so I am posting this here, can anyone help?
Compare the equation for a line through the origin, y = mx, to the equation Fc= mv^2/r, and explain what the slope of the graph of Fc vs. v2 represents. Remember that the m in the equation for a line represents the slope, and the m in the centripetal force equation represents the mass of the stopper.

I don't understand what they are asking

nuttyliaczar · Answer

Well the slope for the force equation in terms of v^2 is going to be m/r, similar to how the slope for the y=mx+b is just m (the coefficient in front of the x). I think that's what it was asking about right?

jellybot23 · Answer

Ohhhh, that makes sense! Thanks so much! I believe that is what they are looking for :)

nuttyliaczar · Answer

Yep no problem. Physics major so I would hope that I can help at least a little

nuttyliaczar · Answer

Although this was more math than anything else

solomonzelman · Answer

$\color{#000000 }{ \displaystyle y=mx  }$
is a line throught the origin with positive slope m
$\color{#000000 }{ \displaystyle F_c=mv^2/r=ma  }$
is the equation of the cetripetal force in terms of centripetal acceleration, where $v^2/r=a$ ($a$-centripetal acceleration).

they are both lines