The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the standard form of the equation for this line? any answer will be of help.
First, do you know what standard form of a line looks like? As in just the general formula.
Okay. So this is not really a calculation problem... it just wants to know the standard form of the equation.. So the standard form is: \[y - y1 = m(x - x1)\]
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That is not the standard form of a line.
i know its just a simple standard form question but every time i do it myself it won't work out like the answers I'm given
Alright so start with that, the standard form of a line is: \[Ax+By=C\] Where A, B, and C are constants. You currently have the line in point-slope form, which is: \[y-y _{1}=m(x-x _{1})\] What would you do to go from what you have to standard form?
make it into a slope intercept and from there into a standard form
Alright, that's a great way of doing it, so multiply it out into slope-intercept form and then post it and I'll check it and we can go from there!
y-7=-1/3(x-6) == y=-1/3x+1 is what i got
Just to double check, is this the same question as in the original post? You wrote originally: \[y+7=(x-10)\] And there's no use solving the wrong problem.
oops sorry hold on yeah sorry wrong problem
No problem, I'm glad I caught it before we went further.
y=-2/5x-17 is what i got for the slope intercept
There is an error somewhere in your work, how about you double check it and then if you can't find it I'll post my work to compare.
(srry the -2/5 didn't copy over something with code) y+7=-2/5(x-10) am i still off??
cause i have y=-2/5-17 i might be off i don't know
Double check what you get on the right side when you distribute the -2/5
forgive me I've forgotten how to do that
That's alright. I'll draw it out (forgive my drawing skills). First you multiply -2/5 times x, and then you multiply -2/5 times 10, and then put them together:|dw:1450995537897:dw|
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