Mathematics
23 Online
OpenStudy (anonymous):
Can someone check my answers?
http://prntscr.com/9iatji
http://prntscr.com/9iatmj
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OpenStudy (anonymous):
@bahrom7893
OpenStudy (anonymous):
@nincompoop
OpenStudy (anonymous):
@Astrophysics
OpenStudy (astrophysics):
How many marbles are there in the first bag?
OpenStudy (anonymous):
20
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OpenStudy (astrophysics):
Right and how many blue marbles are there
OpenStudy (anonymous):
six
OpenStudy (astrophysics):
\[Probability = \frac{ \text{number of favourable outcomes} }{\text {number of possible outcomes} }\]
OpenStudy (astrophysics):
\[\frac{ 6 }{ 20 }\] right
OpenStudy (astrophysics):
Which simplifies to 3/10 good
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OpenStudy (anonymous):
Ty what about the second one?
OpenStudy (astrophysics):
How many marbles in total?
OpenStudy (anonymous):
15
OpenStudy (astrophysics):
Ok so this is multiple parts, so what is the probability of picking a red using what we just learnt?
OpenStudy (anonymous):
8/75?
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OpenStudy (astrophysics):
Ignore the replacing part, what is the probability of just picking the red marble?
OpenStudy (astrophysics):
How many red marbles are there
OpenStudy (anonymous):
5
OpenStudy (astrophysics):
So what are the chances out of 15 that we can get red marbles?
OpenStudy (astrophysics):
It's the same question as we did above look at it for a reference
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OpenStudy (anonymous):
5/15
OpenStudy (astrophysics):
Yes, exactly!
OpenStudy (astrophysics):
So now it asks what the probability is if we replace it, and then pick up another red marble
OpenStudy (anonymous):
5/15 * 1/3 = 1/9?
OpenStudy (astrophysics):
Yes, exactly we multiply the two ratios
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OpenStudy (astrophysics):
5/15*5/15
OpenStudy (astrophysics):
or 1/3*1/3 :)
OpenStudy (anonymous):
Thanks.