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Mathematics 23 Online
OpenStudy (anonymous):

Can someone check my answers? http://prntscr.com/9iatji http://prntscr.com/9iatmj

OpenStudy (anonymous):

@bahrom7893

OpenStudy (anonymous):

@nincompoop

OpenStudy (anonymous):

@Astrophysics

OpenStudy (astrophysics):

How many marbles are there in the first bag?

OpenStudy (anonymous):

20

OpenStudy (astrophysics):

Right and how many blue marbles are there

OpenStudy (anonymous):

six

OpenStudy (astrophysics):

\[Probability = \frac{ \text{number of favourable outcomes} }{\text {number of possible outcomes} }\]

OpenStudy (astrophysics):

\[\frac{ 6 }{ 20 }\] right

OpenStudy (astrophysics):

Which simplifies to 3/10 good

OpenStudy (anonymous):

Ty what about the second one?

OpenStudy (astrophysics):

How many marbles in total?

OpenStudy (anonymous):

15

OpenStudy (astrophysics):

Ok so this is multiple parts, so what is the probability of picking a red using what we just learnt?

OpenStudy (anonymous):

8/75?

OpenStudy (astrophysics):

Ignore the replacing part, what is the probability of just picking the red marble?

OpenStudy (astrophysics):

How many red marbles are there

OpenStudy (anonymous):

5

OpenStudy (astrophysics):

So what are the chances out of 15 that we can get red marbles?

OpenStudy (astrophysics):

It's the same question as we did above look at it for a reference

OpenStudy (anonymous):

5/15

OpenStudy (astrophysics):

Yes, exactly!

OpenStudy (astrophysics):

So now it asks what the probability is if we replace it, and then pick up another red marble

OpenStudy (anonymous):

5/15 * 1/3 = 1/9?

OpenStudy (astrophysics):

Yes, exactly we multiply the two ratios

OpenStudy (astrophysics):

5/15*5/15

OpenStudy (astrophysics):

or 1/3*1/3 :)

OpenStudy (anonymous):

Thanks.

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