Using a directrix of y = −3 and a focus of (2, 1), what quadratic function is created?
omg guess
a
how did you do that
i sort of worked it out before but i am not sure if I was right
am I?
yes
thank you :)
pls parth is this a parabola
ye
ok
ok
May i know the equation of parabola ? @Parthkohli
May i know the standard equation of parabola
There are several forms of the equation of a parabola. The one you need here involves "p". "p" is the distance between the vertex and the focus, also the distance between the vertex and the directrix. I'd suggest you draw this situation and share y our drawing here. Specifically, please draw the directrix line, the focus and the vertex (which is halfway between the directrix and the focus. Please look up "equations of parabolas" and look for the one that includes "p."
@shamim No need. What you do is you take a point \((x,y)\) and equate distances between focus and directrix.
@ FLVSKidd: you've had this question posted for 19+ hours now. I see you're online now, but "just looking around." Do you want to finish this problem, or shall we close it? I need your involvement in order to help you meaningfully.
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