Question

Evaluate cos (Tan^-1 squareroot of 3/3 + sin^-1 1/2). I think it's 1/2.

Answer 1

cos(Arctan (square root of 3)/3 + Arcsin 1/2)

Answer 2

@mathstudent55

Answer 3

@Michele_Laino

Answer 4

Is this the problem?

\(\cos [\tan^{-1} (\dfrac{\sqrt 3}{3}) + \sin^{-1} \dfrac{1}{2}]\)

Answer 5

yes

Answer 6

As usual, we do this one step at a time.
We start with the arctan and the arcsin.

\(=\cos [30^o + 30^o]\)

\(= \cos 60^o\)

\(= \dfrac{1}{2} \)

You are correct.

Answer 7

thanx

Answer 8

yw