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Solve the following system of equations. 2x + y = 3 x = 2y - 1 I think {(1,1)} <-- this is the answer. Is that correct??
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\(\color{#000000 }{ \displaystyle 2x + y = 3 \quad \Longrightarrow\quad2\color{#ff0000}{\left(2y-1\right)}+y=3 }\) \(\color{#000000 }{ \displaystyle x = 2y - 1}\)
I am just showing you that given the second equation, you can substitute 2y-1 instead of x, into the first equation.
\(\color{#000000 }{ \displaystyle 2\color{#ff0000}{\left(2y-1\right)}+y=3 }\) Can you solve for y?
your answer is correct . show your work
HI!!
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it is an easy check, put x = 1, y = 1 and see if they both work (they do)
Oh, lol, I didn't see the answer (just woke up).... I apologize:)
It's Ok :)
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