Question

Solve the following system of equations.

2x + y = 3
x = 2y - 1

I think {(1,1)} <-- this is the answer. Is that correct??

Answer 1

\(\color{#000000 }{ \displaystyle 2x + y = 3 \quad \Longrightarrow\quad2\color{#ff0000}{\left(2y-1\right)}+y=3 }\)
\(\color{#000000 }{ \displaystyle x = 2y - 1}\)

Answer 2

I am just showing you that given the second equation, you can substitute 2y-1 instead of x, into the first equation.

Answer 3

\(\color{#000000 }{ \displaystyle 2\color{#ff0000}{\left(2y-1\right)}+y=3 }\)

Can you solve for y?

Answer 4

your answer is correct .
show your work

Answer 5

HI!!

Answer 6

it is an easy check, put x = 1, y = 1 and see if they both work (they do)

Answer 7

Oh, lol, I didn't see the answer (just woke up)....
I apologize:)

Answer 8

It's Ok :)