Question

PLEASE HELP WILL FAN AND MEDAL

Question attached in comments

Answer 1

what is \(f(-3)\)? you need that first

Answer 2

I don't know how to get f(-3)...

Answer 3

\[f(x)=x+4\\
f(\spadesuit)=\spadesuit+4\]

Answer 4

\[f(\xi)=\xi +4\\
f(-3)=-3+4\]

Answer 5

so 4 is why and somehow we get -3 for x?

Answer 6

you are asked for \(g\circ f(-3)\) right?

Answer 7

that means that \(x=-3\)
it is going to take two steps to compute \(g\circ f(-3)\)
the first step is to find \(f(-3)\)

Answer 8

do you know how to evaluate a function at a number?

Answer 9

here is an example
suppose \(h(x)=x^2+1\)
that makes \(h(5)=5^2+1=26\)

Answer 10

in other words, plug in the number where you see the variable, compute the result

Answer 11

One second while I try..

Answer 12

ok
this is your first job\[f(x)=x+4\\f(-3)=-3+4=?\]

Answer 13

1?

Answer 14

yes \(-3+4=1\)

Answer 15

ok, next job is an easy one, compute \(g(1)\)

Answer 16

g^3?

Answer 17

\[g(x)=x^3\] right?

Answer 18

Yea?

Answer 19

so \[g(\heartsuit)=\heartsuit^3\] and \[g(1)=1^3=?\]

Answer 20

3?

Answer 21

no

Answer 22

\[1\times 3=3\] but \(1^3=1\times 1\times 1\)

Answer 23

1*1*1 is just 1..

Answer 24

yes it is

Answer 25

so \[g\circ f(-3)=g(f(-3))=g(1)=1\]

Answer 26

i.e. 1 is your final answer

Answer 27

Thank you... Is there any way you'd help with like 8 more please? If I get anything else wrong I fail my assignment all over again

Answer 28

ok sure

Answer 29

Thank you so much. I;'ll get the next one up momentarily