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@pooja195
\[\sqrt[3]{\frac{ 24 }{ 125 }}\]
@pooja195
@satellite73
Are you trying to figure out the square root?
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it just says simply and combine
i would not take that approach since \(5^3=125\) you know \(\sqrt[3]{125}=5\)
so you have \[\frac{\sqrt[3]{24}}5\] as a first step
now 24 is not a perfect cube, but 8 is since \(2^3=8\) that makes \[\sqrt[3]{24}=\sqrt[3]{8\times 3}=\sqrt[3]{8}\sqrt[3]{3}=2\sqrt[3]{3}\]
2 cubed radical 3 over 5
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