Question

5. Simplify the radical expression.
Square root 20x^13y^5/5xy^7
A) square root 4x^12/y^2
B) 2x^6/y
C) 2 square root x^12/y^2
D) 2x^6y

Answer 1

again same concepts

Answer 2

Start with \[\sqrt{20}\] To take this out of the radical, you need to find a squared term that's a factor of 20. What is that term?

Answer 3

None of the answers appear to be correct as is.. Are you sure about your syntax?

Answer 4

check them @DannyO19 newly because there is the right answer

Answer 5

commen this is easy

Answer 6

so sqrt20/5 = sqrt4 = 2
yes ?

Answer 7

yes

Answer 8

sqrtx^13/x = sqrtx^12 = x^6
yes ?

Answer 9

Yeah, sure

Answer 10

and sqrty^5/y^7 = sqrt(1/y^2) = 1/y

so tha right answer will be B.

ok. ?

Answer 11

do you understand it @Answers101 ?

Answer 12

No, that's not right

Answer 13

yes but in denominator are x and y^7
yes ?

Answer 14

do you can rewrite this exercise without denominator for you can check it sure ?

Answer 15

with exponents negativ - this is easy - try it

Answer 16

The problem is that once we factor out the 2 we get the Sqrt of ( (x^13y^5)/(xy^5) ) an expression that can't be further simplified because the numerator and denominator aren't like terms.

Answer 17

square root 20x^13y^5/5xy^7 = sqrt(20x^13y^5*5^(-1)*x^(-1)*y^(-7) =
=sqrt(4*5*5^(-1)*x^(13-1)*y^(5-7) ) = 2sqrt(x^12*y^(-2) ) = (2x^6)/y so this mean that B is right answer sure

Answer 18

@Answers101 do you understand it why B. is the right answer ?

Answer 19

@mathmale do you understand what have said @Danny ?

Answer 20

@ganeshie8 please your opinion about this ?

Answer 21

5. Simplify the radical expression.
Square root 20x^13y^5/5xy^7 do you mean the following? See below \[\frac{ 20x ^{13}*y^5 }{ 5xy^7 }??\]
A) square root 4x^12/y^2
B) 2x^6/y
C) 2 square root x^12/y^2
D) 2x^6y

Answer 22

Please either verify this, or correct it.

Answer 23

@mathmale who have said you this above ?

Answer 24

That comment was directed at Answers101.

Answer 25

ok. thanks