Please help! Will fan and medal!!!!! Question attached in comments. I think it is NOT in the domain
@DannyO19
So plugging in -6x+3 into your function f(x)..
What would you get?
-2
I agree with Danny that it's important that you form f(g(x)) using the two given functions. Only after you've done that are you ready to think about the domain of f(g(x)).
Your equation for f of g(x) So Sqrt of -6x+1
I get 2.44948-
You'd understand more if you would PLEASE form f(g(x)) from the given functions. Not being able to see what you've done, I can't give you meaningful feedback.
I literally did what he said. I did \[\sqrt{-6(-2+1)}\] just like he asked. All I'm ever doing is trying to fill in as I'm told you don't have to yell I'm already frustrated enough ._.
If f(x)=Sqrt(x-2) and g(x)=-6x-3, then f(g(x)) =\[\sqrt{(-6x-3) -2}\]
which is quite different. Thank you for showing your work. In \[f(x)=\sqrt{(x)-2}\]
Alright. So since that says domain error I was correct and it is not in the domain?
"x" shows up twice. Replace the first x by "g(x)" . Replace the 2nd x by (-6-3).
So then it is in the domain?
From your comments I see you are tired and just want to finish, even if you don't truly understand how we arrive at the correct answer. I'm sorry you're frustrated. I ask you to simplify my expression for f(g(x)), shown above.
(-6x-3)-2=??
Well I did \[\sqrt{(-6*5-3)-2}\] and my calculator said domain error?
When i take away the sqrt i get -35
(-6*x-3)-2 comes out to -6x-5. Yes, if you evaluate this a t x= 5 you do get -35. What is the domain of the sqrt function? Next: Is 5 in that domain?
yes?
For me, the question is WHY? the domain of the Sqrt function is [0, infinity]. is -35 a member of that set?
no
right. you get that -35 when you let x=5. Since the that -35 is not within the domain of the sqrt functin, 5 is not in the domain of your f(g(x)).
It's asking if -5 is....
What do you think? Evaluate Sqrt((-6*[-5]-2), please.
\[\sqrt{-6(-5)-2}=?\]
Note: you must do multiplication before adding or subtraction. Order of Operations rules.
I think no
Please evaluate the expression I've typed out for you. Multiply first, subtract 2nd.
30-2 = 28
is that within the domain of the Sqrt(x) function?
yes
The domain of the sqrt function is [0, inf] and 28 is within that domain. therefore, -5 is part of the domain of your f(g(x)).
Still there? You have successfully worked thru this question. Congrats. Sorry it took so long. Take care, see you again.
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