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What is the slope-intercept form of the function that contains the points (6, 2) and (4, 8)? y=___x + ___
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first, find the slope
....sorry brain fart. lol how do i do that again?
slope=(y2-y1)/(x2-x1)
Well first find the slope, using the following formula: \[m = \frac{ y_{2}-y _{1} }{ x _{2}-x _{1} }\] where your coordinates represent \[(x_1,y_1)~~\text{and}~~(x_2,y_2)\] Once you manage to get that, plug in m and your first coordinates in the point - slope form: \[y-y _{1}=m(x-x _{1})\] do some little algebra and eventually you will have slope - intercept form \[y=mx+b\]
(8-2)/(4-6)
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slope is -3
i got that too
now use one of the points and the slope. y-y=m(x-x)
(6, 2) and slope =-3 y-2=-3(x-6)
solve for y
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y-2=-3x+18
-3x+ 20
yes y=-3x+20
yay
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