Mathematics
19 Online
OpenStudy (anonymous):
ahhhhh help!! arithmetic sequencessss
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[a _{n}=2a _{n-1}+3\]
OpenStudy (xapproachesinfinity):
the question?
OpenStudy (anonymous):
\[a_{1}=2\]
OpenStudy (anonymous):
That is all it gives me
OpenStudy (xapproachesinfinity):
what does the question say?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (xapproachesinfinity):
find what?
OpenStudy (anonymous):
I'm supposed to find the first 5 terms of the sequence.
OpenStudy (xapproachesinfinity):
ok so you are given the first term a1=1
to find the next term you use the explicit formula
\[a_n=2a_{n-1}+3\]
\[a_2=2a_{2-1}+3=2a_1+3=2(1)+3=5\]
OpenStudy (xapproachesinfinity):
now you got second term you use it to find the next term
\[a_3=2a_2+3=2(5)+3=13\]
OpenStudy (xapproachesinfinity):
you continue in this manner till you reach the fifth term
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I think what is confusing me is that \[a _{1}\] shouldn't equal 2 according to the function.
OpenStudy (xapproachesinfinity):
i can't grasp what you are trying to say?
a1 is given to you it is not 2 it is 11
OpenStudy (xapproachesinfinity):
it 1*
OpenStudy (xapproachesinfinity):
they gave you the formula and a1=1
OpenStudy (anonymous):
Yeah, but the assignment says it is 2 for some reason.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (xapproachesinfinity):
oh sorry my fault hehe i thought i saw 1
it is a1=2
truly sorry not enough attention
OpenStudy (xapproachesinfinity):
the method won't change though
OpenStudy (xapproachesinfinity):
\(a_1=2\)
\[a_2=2a_1+3=2(2)+3=7\]
\[a_3=2a_2+3=2(7)+3=17\]
\[a_4=2a_3+3=2(17)+3=37\]
OpenStudy (xapproachesinfinity):
you need one more go for it
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[a_{5}=2a _{4}+3=2(37)+3=77\]
OpenStudy (xapproachesinfinity):
yes
OpenStudy (xapproachesinfinity):
you see that at each step we are using the previous term to find the next one
OpenStudy (anonymous):
Thank you :)
OpenStudy (xapproachesinfinity):
np!