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Mathematics 19 Online
OpenStudy (anonymous):

ahhhhh help!! arithmetic sequencessss

OpenStudy (anonymous):

\[a _{n}=2a _{n-1}+3\]

OpenStudy (xapproachesinfinity):

the question?

OpenStudy (anonymous):

\[a_{1}=2\]

OpenStudy (anonymous):

That is all it gives me

OpenStudy (xapproachesinfinity):

what does the question say?

OpenStudy (xapproachesinfinity):

find what?

OpenStudy (anonymous):

I'm supposed to find the first 5 terms of the sequence.

OpenStudy (xapproachesinfinity):

ok so you are given the first term a1=1 to find the next term you use the explicit formula \[a_n=2a_{n-1}+3\] \[a_2=2a_{2-1}+3=2a_1+3=2(1)+3=5\]

OpenStudy (xapproachesinfinity):

now you got second term you use it to find the next term \[a_3=2a_2+3=2(5)+3=13\]

OpenStudy (xapproachesinfinity):

you continue in this manner till you reach the fifth term

OpenStudy (anonymous):

I think what is confusing me is that \[a _{1}\] shouldn't equal 2 according to the function.

OpenStudy (xapproachesinfinity):

i can't grasp what you are trying to say? a1 is given to you it is not 2 it is 11

OpenStudy (xapproachesinfinity):

it 1*

OpenStudy (xapproachesinfinity):

they gave you the formula and a1=1

OpenStudy (anonymous):

Yeah, but the assignment says it is 2 for some reason.

OpenStudy (anonymous):

OpenStudy (xapproachesinfinity):

oh sorry my fault hehe i thought i saw 1 it is a1=2 truly sorry not enough attention

OpenStudy (xapproachesinfinity):

the method won't change though

OpenStudy (xapproachesinfinity):

\(a_1=2\) \[a_2=2a_1+3=2(2)+3=7\] \[a_3=2a_2+3=2(7)+3=17\] \[a_4=2a_3+3=2(17)+3=37\]

OpenStudy (xapproachesinfinity):

you need one more go for it

OpenStudy (anonymous):

\[a_{5}=2a _{4}+3=2(37)+3=77\]

OpenStudy (xapproachesinfinity):

yes

OpenStudy (xapproachesinfinity):

you see that at each step we are using the previous term to find the next one

OpenStudy (anonymous):

Thank you :)

OpenStudy (xapproachesinfinity):

np!

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