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OpenStudy (gokuporter):
@mathstudent55 Is this correct?
OpenStudy (dayakar):
equation of the line whose slope m= -2
and passing the point (x1, y1) = (8 ,12) is in the form
y-y1 = m (x - x1)
can u plug above values and get the equation
OpenStudy (marihelenh):
\[(y-y _{1})=m(x-x _{1})\]
OpenStudy (gokuporter):
y-12 = -2(x-8)
OpenStudy (dayakar):
very good
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OpenStudy (dayakar):
write it in the form y = mx +c
OpenStudy (dayakar):
r u doing
OpenStudy (gokuporter):
It's Slope-Intercept Form .-.
OpenStudy (gokuporter):
y=mx + b
OpenStudy (dayakar):
yes ,ur answer should be like this form
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OpenStudy (gokuporter):
Is the answer I wrote correct?
OpenStudy (anonymous):
yes
OpenStudy (dayakar):
y-12 =-2x +16
y = -2x +16+12
y= -2x +28
OpenStudy (gokuporter):
Oh ok .-.
OpenStudy (dayakar):
):
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OpenStudy (gokuporter):
Why did you add?
OpenStudy (gokuporter):
@dayakar Why did you add?
pooja195 (pooja195):
That's not right....
pooja195 (pooja195):
y=mx+b
slope is given
y=-2x+b
to find b we must plug in the 2 given numbers in the coordinates in the right spot (x,y)
12=-2(8)+b
solve from here
OpenStudy (gokuporter):
12=-16+b? @pooja195
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pooja195 (pooja195):
ok continue
OpenStudy (gokuporter):
-28?
OpenStudy (gokuporter):
How do I continue on from there?
OpenStudy (gokuporter):
@pooja195 ?
pooja195 (pooja195):
12+16=?
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