Please Help??? Find a point that would fall on the line that has a slope of ½ and intersects (3, ‐4)
\[(y-y _{1})=m(x-x _{1})\]
m=slope x1=3 y1=-4
This will give you your line, from there, you can pick a point,
SD
Well, actually, slope is rise over run (y/x), so you could add 1 to the y and 2 to the x value
that is my graph dont mid the top part
Ok, so it gives you the two options, the slope is positive, so the line has to go from down to up|dw:1451845922426:dw|
would it be either one of those? it is one half so rise over run would be up `1 over 2
Exactly, it is one of them, one is just a positive rise and the other is a negative
which one would it be though>? that is what i am not sure about.
is 1/2 positive or negative
positive
|dw:1451846119494:dw|
Which point would a positive line go through?
1, -4?
It will go up one unit, and right two units. See what point that corresponds with.
oooh so it would be 5,-3
Yes, great! I hope you understand, let me know if you don't
Yes I do now!! Thanks so much for helping!!
Join our real-time social learning platform and learn together with your friends!