Question

Find a cubic function with the given zeros.

6, -3, 5

Answer 1

When you have found the roots or zeros of polynomials they can be written as factors... Like (x+2)(x-3)= x^2-x-6

Answer 2

im sorry im very lost lol

Answer 3

What would be the zeros for (x+2)(x-3)?

Answer 4

like wha happens if i foil itt

Answer 5

They would be -2 and 3 because the zeros are when y=0

Answer 6

0=(x+2)(x-3)

Answer 7

ok i think get it alittle

Answer 8

so six can be x-6

Answer 9

See when I make x=-2 or 3 then y does in fact equal zero

Answer 10

y=(x+2)(x-3)

Answer 11

So now in order to get a cubic function you'd have to have x times x times x to get x^3

Answer 12

Then how about (x+a)(x+b)(x+c) form?

Answer 13

Your zeros are 6 , -3 and 5 so for each factor x will equal 6 then -3 then 5 in order to get zero with that factor...

Answer 14

ok so i think i git it is it x^3-8x^2-3x+90

Answer 15

What factors did you use?

Answer 16

How do you make 6 equal zero, -3 equal zero and 5 equal zero, get it?

Answer 17

x-6 x+3 and x-5

Answer 18

(x-6)(x+3)(x-5) is a factored form of a cubic function
do you need to expand it?

Answer 19

If the question doesn't say expand that's fine that way..

Answer 20

more like i foiled it

Answer 21

Ok, if you need to do that you can...

Answer 22

alright so i foiled it and it gave me x^3-8x^2-3x+90

Answer 23

Looks good

Answer 24

thank you

Answer 25

It's also called expand (x-6)(x+3)(x-5) if you want to get answers fast on calculators alternatively to the foil method.