Question

Can someone help me with these two problems?
Write the equation in logarithmic form.
(1/3)^3=1/27

Write the equation in exponential form.
log3 1/9= -2

Answer 1

HI!!

Answer 2

\[\huge b^x=y\iff \log_b(y)=x\] you should be able to switch back and forth quickly

Answer 3

for example \[10^3=1000\iff \log_{10}(1000)=3\]and \[2^{-4}=\frac{1}{16}\iff \log_2(\frac{1}{16})=-4\]

Answer 4

Okay... that makes sense. @misty1212

Answer 5

so \[\left(\frac{1}{3}\right)^3=\frac{1}{27}=\iff?\]

Answer 6

log1/3 (1/27)=3
Right? @misty1212

Answer 7

yes exactly

Answer 8

now for the other one you have to translate the other way \[?\iff \log_3(\frac{1}{9})=-2\]

Answer 9

did you get it or are you stuck?

Answer 10

It would be 3^-2=1/9 correct? @misty1212

Answer 11

yes

Answer 12

Wait that can't be right because it's not a choice... oops

Answer 13

which is true right? since \[3^{-2}=\frac{1}{3^2}=\frac{1}{9}\]

Answer 14

yes it is right

Answer 15

Ohhh I see..

Answer 16

Thanks so much @misty1212 you were so helpful! :)

Answer 17

\[\color\magenta\heartsuit\]